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User: James Stein

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James Stein has authored 1 sequences.

A242709 Nonequivalent ways to place two different markers (e.g., a pair of Go stones, black and white) on an n X n grid.

Original entry on oeis.org

0, 2, 12, 33, 85, 165, 315, 518, 846, 1260, 1870, 2607, 3627, 4823, 6405, 8220, 10540, 13158, 16416, 20045, 24465, 29337, 35167, 41538, 49050, 57200, 66690, 76923, 88711, 101355, 115785, 131192, 148632, 167178, 188020, 210105, 234765, 260813, 289731, 320190
Offset: 1

Author

James Stein, May 21 2014

Keywords

Comments

We say two placements are equivalent if one can be obtained from the other by rotating or reflecting the grid.
The formula was derived by categorizing and counting grid cells into four exclusive categories: central cell (if any); other diagonal cells, other horizontal and vertical midline cells (if any), and all others (in eight triangular regions) (if any); then determining for each category, how many ways a white stone could be placed in each category, given the category in which the black stone was placed prior. The sequence was verified by another program which generated all positions, removed reflections and rotations, and tallied the residue.

Crossrefs

Cf. A014409 (with indistinguishable checkers)

Programs

  • Magma
    [n*(n^3 + n*3^(n mod 2) - 2*2^(n mod 2))/8: n in [1..50]]; // Wesley Ivan Hurt, May 21 2014
  • Maple
    A242709:=n->n*(n^3 + n*3^(n mod 2) - 2*2^(n mod 2))/8; seq(A242709(n), n=1..50); # Wesley Ivan Hurt, May 21 2014
  • Mathematica
    f[n_] := If[OddQ[n], (n^3 + 3 n - 4), (n^3 + n - 2)] n/8;
    Table[f[n], {n, 1, 40}]
  • PARI
    concat(0, Vec(-x^2*(x^5+x^4+7*x^3+5*x^2+8*x+2)/((x-1)^5*(x+1)^3) + O(x^100))) \\ Colin Barker, May 21 2014
    

Formula

For odd n, a(n) = n*(n^3 + 3*n - 4)/8.
For even n, a(n) = n*(n^3 + n - 2)/8.
G.f.: -x^2*(x^5+x^4+7*x^3+5*x^2+8*x+2) / ((x-1)^5*(x+1)^3). - Colin Barker, May 21 2014
a(n) = n*(n^3 + n*3^(n mod 2) - 2*2^(n mod 2))/8. - Wesley Ivan Hurt, May 21 2014