A010099 a(n) = a(n-1)*a(n-2) with a(0)=1, a(1)=4.
1, 4, 4, 16, 64, 1024, 65536, 67108864, 4398046511104, 295147905179352825856, 1298074214633706907132624082305024, 383123885216472214589586756787577295904684780545900544
Offset: 0
Links
- Indranil Ghosh, Table of n, a(n) for n = 0..17
- W. W. Adams and J. L. Davison, A remarkable class of continued fractions, Proc. Amer. Math. Soc. 65 (1977), 194-198.
- P. G. Anderson, T. C. Brown, P. J.-S. Shiue, A simple proof of a remarkable continued fraction identity, Proc. Amer. Math. Soc. 123 (1995), 2005-2009.
- D. Bowman, A new generalization of Davison's theorem, Fib. Quart. Volume 26 (1988), 40-45
Crossrefs
Programs
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Maple
a[ -1]:=1:a[0]:=4: a[1]:=4: for n from 2 to 13 do a[n]:=a[n-1]*a[n-2] od: seq(a[n], n=-1..10); # Zerinvary Lajos, Mar 19 2009
Formula
a(n) = 4^Fibonacci(n).
Comments