A010878 a(n) = n mod 9.
0, 1, 2, 3, 4, 5, 6, 7, 8, 0, 1, 2, 3, 4, 5, 6, 7, 8, 0, 1, 2, 3, 4, 5, 6, 7, 8, 0, 1, 2, 3, 4, 5, 6, 7, 8, 0, 1, 2, 3, 4, 5, 6, 7, 8, 0, 1, 2, 3, 4, 5, 6, 7, 8, 0, 1, 2, 3, 4, 5, 6, 7, 8, 0, 1, 2, 3, 4, 5, 6, 7, 8, 0, 1, 2, 3, 4, 5, 6, 7, 8, 0, 1, 2, 3, 4, 5, 6, 7, 8, 0, 1, 2, 3, 4, 5, 6, 7, 8, 0, 1, 2, 3, 4, 5
Offset: 0
Links
- Ely Golden, Table of n, a(n) for n = 0..10000
- Index entries for linear recurrences with constant coefficients, signature (0,0,0,0,0,0,0,0,1).
Crossrefs
Programs
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Haskell
a010878 = (`mod` 9) a010878_list = cycle [0..8] -- Reinhard Zumkeller, Jan 09 2013
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Maple
A010878 := proc(n) modp(n,9) ; end proc: seq(A010878(n),n=0..100) ; # R. J. Mathar, Sep 09 2015
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Mathematica
Array[Mod[#, 9]&, 105, 0] (* Jean-François Alcover, Jan 30 2018 *) PadRight[{},120,Range[0,8]] (* Harvey P. Dale, Dec 19 2018 *)
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PARI
a(n)=n%9 \\ Charles R Greathouse IV, Sep 24 2015
Formula
Complex representation: a(n)=(1/9)*(1-r^n)*sum{1<=k<9, k*product{1<=m<9,m<>k, (1-r^(n-m))}} where r=exp(2*pi/9*i) and i=sqrt(-1). Trigonometric representation: a(n)=(256/9)^2*(sin(n*pi/9))^2*sum{1<=k<9, k*product{1<=m<9,m<>k, (sin((n-m)*pi/9))^2}}. G.f.: g(x)=(sum{1<=k<9, k*x^k})/(1-x^9). Also: g(x)=x(8x^9-9x^8+1)/((1-x^9)(1-x)^2). - Hieronymus Fischer, May 31 2007
a(n) = n mod 3 + 3*(floor(n/3)mod 3) = A010872(n) + 3*A010872(A002264(n)). - Hieronymus Fischer, Jun 11 2007
a(n) = floor(12345678/999999999*10^(n+1)) mod 10. - Hieronymus Fischer, Jan 03 2013
a(n) = floor(1513361/96855122*9^(n+1)) mod 9. - Hieronymus Fischer, Jan 04 2013
Comments