A016795 a(n) = (3n+2)^7.

128, 78125, 2097152, 19487171, 105413504, 410338673, 1280000000, 3404825447, 8031810176, 17249876309, 34359738368, 64339296875, 114415582592, 194754273881, 319277809664, 506623120463, 781250000000

Offset: 0

Author

N. J. A. Sloane

Keywords

• nonn
• easy

Comments

The inverse binomial transform is 128, 77997, 1941030, 13429962, 39735360, 57561840, 40415760, 11022480, 0 (0 from here on). - R. J. Mathar, May 07 2008

Links

• Index entries for linear recurrences with constant coefficients, signature (8, -28, 56, -70, 56, -28, 8, -1).

Programs

Mathematica

Table[(3n+2)^7,{n,0,100}] (* Mohammad K. Azarian, Jun 15 2016 *)
LinearRecurrence[{8,-28,56,-70,56,-28,8,-1},{128,78125,2097152,19487171,105413504,410338673,1280000000,3404825447},30] (* Harvey P. Dale, Dec 04 2019 *)

Formula

G.f.: (128+77101*x+1475736*x^2+4890287*x^3+3870352*x^4+692499*x^5 +16376*x^6 +x^7) / (x-1)^8. - R. J. Mathar, May 07 2008

Sum_{n>=0} 1/a(n) = (147555*zeta(7) - 28*sqrt(3)*Pi^7)/295245. - Ilya Gutkovskiy, Jun 16 2016