cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

Showing 1-10 of 29 results. Next

A356133 Complement of A026430.

Original entry on oeis.org

2, 4, 7, 11, 13, 17, 20, 22, 25, 29, 32, 34, 38, 40, 43, 47, 49, 53, 56, 58, 62, 64, 67, 71, 74, 76, 79, 83, 85, 89, 92, 94, 97, 101, 104, 106, 110, 112, 115, 119, 122, 124, 127, 131, 133, 137, 140, 142, 146, 148, 151, 155, 157, 161, 164, 166, 169, 173, 176
Offset: 1

Views

Author

Clark Kimberling, Aug 04 2022

Keywords

Examples

			The partial sums of the Thue-Morse sequence A001285 = (1,2,2,1,2,1,1,...) are A026430 = (0,1,3,5,6,8,9,10,...), from which the missing positive integers are (2,4,7,11,...).
		

Crossrefs

Programs

  • Mathematica
    u = Accumulate[1 + ThueMorse /@ Range[0, 2^7]]; (* A026430 *)
    Complement[Range[Max[u]], u]  (* A356133 *)
  • PARI
    a(n) = 3*n - 1 - hammingweight(n-1)%2; \\ Kevin Ryde, Aug 04 2022
    
  • Python
    def A356133(n): return 3*n-(2 if (n-1).bit_count()&1 else 1) # Chai Wah Wu, Mar 01 2023

Formula

a(n) = 3n - A001285(n-1) for n >= 1.

A360392 a(n) = 2 + A026430(n); complement of A360393.

Original entry on oeis.org

3, 5, 7, 8, 10, 11, 12, 14, 16, 17, 18, 20, 21, 23, 25, 26, 28, 29, 30, 32, 33, 35, 37, 38, 39, 41, 43, 44, 46, 47, 48, 50, 52, 53, 54, 56, 57, 59, 61, 62, 63, 65, 67, 68, 70, 71, 72, 74, 75, 77, 79, 80, 82, 83, 84, 86, 88, 89, 90, 92, 93, 95, 97, 98, 100
Offset: 1

Views

Author

Clark Kimberling, Feb 05 2023

Keywords

Crossrefs

Programs

  • Mathematica
    2 + Accumulate[1 + ThueMorse /@ Range[0, 120]]
  • Python
    from itertools import islice, accumulate
    def A360392_gen(): # generator of terms
        yield 3
        blist, s = [1], 3
        while True:
            c = [3-d for d in blist]
            blist += c
            yield from (s+d for d in accumulate(c))
            s += sum(c)
    A360392_list = list(islice(A360392_gen(),30)) # Chai Wah Wu, Feb 22 2023
    
  • Python
    def A360392(n): return n+2+(n-1>>1)+(n-1&1|(n.bit_count()&1^1)) # Chai Wah Wu, Mar 01 2023

A360394 Intersection of A026430 and A360392.

Original entry on oeis.org

3, 5, 8, 10, 12, 14, 16, 18, 21, 23, 26, 28, 30, 33, 35, 37, 39, 41, 44, 46, 48, 50, 52, 54, 57, 59, 61, 63, 65, 68, 70, 72, 75, 77, 80, 82, 84, 86, 88, 90, 93, 95, 98, 100, 102, 105, 107, 109, 111, 113, 116, 118, 120, 123, 125, 128, 130, 132, 134, 136, 138
Offset: 1

Views

Author

Clark Kimberling, Feb 05 2023

Keywords

Comments

This is the first of four sequences that partition the positive integers. Starting with a general overview, suppose that u = (u(n)) and v = (v(n)) are increasing sequences of positive integers. Let u' and v' be their complements, and assume that the following four sequences are infinite:
(1) u ^ v = intersection of u and v (in increasing order);
(2) u ^ v';
(3) u' ^ v;
(4) u' ^ v'.
Every positive integer is in exactly one of the four sequences. The limiting densities of these four sequences are 4/9, 2/9, 2/9, and 1/9, respectively (and likewise for A360402-A360405).
For A360394, u, v, u', v', are sequences obtained from the Thue-Morse sequence, A026430, as follows:
u = A026530 = (1,3,5,6,8,9,10, 12, ... ) = partial sums of A026430
u' = A356133 = (2,4,7,11,13,17, 20, ... ) = complement of u
v = u + 1 = A285954, except its initial 1
v' = complement of v.

Examples

			(1)  u ^ v = (3, 5, 8, 10, 12, 14, 16, 18, 21, 23, 26, 28, 30, 33, ...) =  A360394
(2)  u ^ v' = (1, 6, 9, 15, 19, 24, 27, 31, 36, 42, 45, 51, 55, 60, ...) =  A360395
(3)  u' ^ v = (7, 11, 17, 20, 25, 29, 32, 38, 43, 47, 53, 56, 62, ...) = A360396
(4)  u' ^ v' = (2, 4, 13, 22, 34, 40, 49, 58, 64, 76, 85, 94, 106, ...) = A360397
		

Crossrefs

Programs

  • Mathematica
    z = 400;
    u = Accumulate[1 + ThueMorse /@ Range[0, z]];   (* A026430 *)
    u1 = Complement[Range[Max[u]], u];  (* A356133 *)
    v = u + 2 ; (* A360392 *)
    v1 = Complement[Range[Max[v]], v];  (* A360393 *)
    Intersection[u, v]     (* A360394 *)
    Intersection[u, v1]    (* A360395 *)
    Intersection[u1, v]    (* A360396 *)
    Intersection[u1, v1]   (* A360397 *)

A359277 Intersection of A026430 and (1 + A285953).

Original entry on oeis.org

6, 9, 10, 15, 16, 19, 24, 27, 28, 31, 36, 37, 42, 45, 46, 51, 52, 55, 60, 61, 66, 69, 70, 73, 78, 81, 82, 87, 88, 91, 96, 99, 100, 103, 108, 109, 114, 117, 118, 121, 126, 129, 130, 135, 136, 139, 144, 145, 150, 153, 154, 159, 160, 163, 168, 171, 172, 175
Offset: 1

Views

Author

Clark Kimberling, Jan 26 2023

Keywords

Comments

This is the first of three sequences that partition the positive integers. Taking u = A026430 and v = 1 + A285953 (which is A285953 except for its initial 1), the three sequences are (1) u ^ v = intersection of u and v (in increasing order); (2) u ^ v'; and (3) u' ^ v. The limiting density of each of these is 1/3.

Examples

			(1)  u ^ v = (6, 9, 10, 15, 16, 19, 24, 27, 28, 31, 36, 37, ...) =    A359277
(2)  u ^ v' = (1, 3, 5, 8, 12, 14, 18, 21, 23, 26, 30, 33, 35, ...) =  A285953, except for the initial 1
(3)  u' ^ v = (2, 4, 7, 11, 13, 17, 20, 22, 25, 29, 32, 34, 38, ...) = A356133
		

Crossrefs

Cf. A026530, A285954, A356133, A359352 to A360139) (results of compositions instead of intersections).

Programs

  • Mathematica
    z = 200;
    u = Accumulate[1 + ThueMorse /@ Range[0, z]]   (* A026430 *)
    u1 = Complement[Range[Max[u]], u]  (* A356133 *)
    v = u + 1
    v1 = Complement[Range[Max[v]], v]
    Intersection[u, v]    (* A359277 *)
    Intersection[u, v1]   (* A285953 *)
    Intersection[u1, v]   (* A356133 *)

A359352 a(n) = A026430(1 + A026430(n)).

Original entry on oeis.org

3, 6, 9, 10, 14, 15, 16, 19, 23, 24, 26, 28, 30, 33, 36, 37, 41, 42, 44, 46, 48, 51, 54, 55, 57, 60, 63, 65, 68, 69, 70, 73, 77, 78, 80, 82, 84, 87, 90, 91, 93, 96, 99, 100, 103, 105, 107, 109, 111, 114, 117, 118, 121, 123, 125, 128, 130, 132, 134, 136, 138
Offset: 1

Views

Author

Clark Kimberling, Jan 26 2023

Keywords

Comments

This is the first of four sequences that partition the positive integers. Suppose that u = (u(n)) and v = (v(n)) are increasing sequences of positive integers. Let u' and v' be their (increasing) complements, and consider these four sequences:
(1) u o v, defined by (u o v)(n) = u(v(n));
(2) u o v';
(3) u' o v;
(4) v' o u'.
Every positive integer is in exactly one of the four sequences. Their limiting densities are 4/9, 2/9, 2/9, 1/9, respectively.

Examples

			(1) u o v = (3, 6, 9, 10, 14, 15, 16, 19, 23, 24, 26, 28, 30, 33, 36, 37, 41, ...) = A359352
(2) u o v' = (1, 5, 8, 12, 18, 21, 27, 31, 35, 39, 45, 50, 52, 59, 61, 66, 72, ...) = A359353
(3) u' o v = (4, 11, 17, 20, 25, 29, 32, 38, 43, 47, 49, 56, 58, 64, 71, 74, ...) = A360134
(4) u' o v' = (2, 7, 13, 22, 34, 40, 53, 62, 67, 76, 89, 97, 104, 115, 122, ...) = A360135
		

Crossrefs

Cf. A026530, A359352, A285953, A285954, A359277 (intersections instead of results of composition), A359353-A360139.

Programs

  • Mathematica
    z = 2000; zz = 100;
    u = Accumulate[1 + ThueMorse /@ Range[0, 600]]; (* A026430 *)
    u1 = Complement[Range[Max[u]], u];  (* A356133 *)
    v = u + 1;  (* A285954 *)
    v1 = Complement[Range[Max[v]], v]; (* A285953 *)
    Table[u[[v[[n]]]], {n, 1, zz}]     (* A359352 *)
    Table[u[[v1[[n]]]], {n, 1, zz}]    (* A359353 *)
    Table[u1[[v[[n]]]], {n, 1, zz}]    (* A360134 *)
    Table[u1[[v1[[n]]]], {n, 1, zz}]   (* A360135 *)
  • Python
    def A359352(n): return (m:=n+1+(n-1>>1)+(n-1&1|(n.bit_count()&1^1)))+(m-1>>1)+(m-1&1|(m.bit_count()&1^1)) # Chai Wah Wu, Mar 01 2023

A360398 a(n) = A026430(1 + A360392(n)).

Original entry on oeis.org

5, 8, 10, 12, 15, 16, 18, 21, 24, 26, 27, 30, 31, 35, 37, 39, 42, 44, 45, 48, 50, 52, 55, 57, 59, 61, 65, 66, 69, 70, 72, 75, 78, 80, 81, 84, 86, 88, 91, 93, 95, 98, 100, 102, 105, 107, 108, 111, 113, 116, 118, 120, 123, 125, 126, 129, 132, 134, 135, 138
Offset: 1

Views

Author

Clark Kimberling, Feb 10 2023

Keywords

Comments

This is the first of four sequences that partition the positive integers. Suppose that u = (u(n)) and v = (v(n)) are increasing sequences of positive integers. Let u' and v' be their (increasing) complements, and consider these four sequences:
(1) u o v, defined by (u o v)(n) = u(v(n));
(2) u o v';
(3) u' o v;
(4) v' o u'.
Every positive integer is in exactly one of the four sequences. Their limiting densities are 4/9, 2/9, 2/9, 1/9 (and likewise for A360394-A360397 and A360402-A360405).

Examples

			(1)  u o v = (5, 8, 10, 12, 15, 16, 18, 21, 24, 26, 27, 30, 31, 35, 37, 39, ...) = A360398
(2)  u o v' = (1, 3, 6, 9, 14, 19, 23, 28, 33, 36, 41, 46, 51, 54, 60, 63, 68, ...) = A360399
(3)  u' o v = (7, 13, 20, 22, 29, 32, 34, 40, 47, 49, 53, 58, 62, 67, 74, 76, ...) = A360400
(4)  u' o v' = (2, 4, 11, 17, 25, 38, 43, 56, 64, 71, 79, 92, 101, 106, 119, ...) = A360401
		

Crossrefs

Cf. A026530, A356133, A360392, A360393, A360399, A286355, A286356, A360394 (intersections instead of results of composition), A360402-A360405.

Programs

  • Mathematica
    z = 2000;
    u = Accumulate[1 + ThueMorse /@ Range[0, 600]]; (* A026430 *)
    u1 = Complement[Range[Max[u]], u];  (* A356133 *)
    v = u + 2;  (* A360392 *)
    v1 = Complement[Range[Max[v]], v];    (* A360393 *)
    zz = 100;
    Table[u[[v[[n]]]], {n, 1, zz}]    (* A360398 *)
    Table[u[[v1[[n]]]], {n, 1, zz}]   (* A360399 *)
    Table[u1[[v[[n]]]], {n, 1, zz}]   (* A360400 *)
    Table[u1[[v1[[n]]]], {n, 1, zz}]  (* A360401 *)

A360402 a(n) = A360392(A026430(n)).

Original entry on oeis.org

3, 7, 10, 11, 14, 16, 17, 20, 23, 25, 26, 29, 30, 33, 37, 38, 41, 43, 44, 47, 48, 52, 54, 56, 57, 61, 63, 65, 68, 70, 71, 74, 77, 79, 80, 83, 84, 88, 90, 92, 93, 97, 100, 101, 104, 105, 107, 110, 111, 115, 118, 119, 122, 123, 125, 128, 131, 132, 134, 137
Offset: 1

Views

Author

Clark Kimberling, Mar 11 2023

Keywords

Comments

This is the first of four sequences that partition the positive integers. Suppose that u = (u(n)) and v = (v(n)) are increasing sequences of positive integers. Let u' and v' be their (increasing) complements, and consider these four sequences:
(1) v o u, defined by (v o u)(n) = v(u(n));
(2) v' o u;
(3) v o u';
(4) v' o u.
Every positive integer is in exactly one of the four sequences. Their limiting densities are 4/9, 2/9, 2/9, 1/9, respectively (and likewise for A360394-A360401).

Examples

			(1)  v o u = (3, 7, 10, 11, 14, 16, 17, 20, 23, 25, 26, 29, 30, 33, 37, ...) = A360402
(2)  v' o u = (1, 4, 9, 13, 19, 22, 24, 31, 36, 40, 42, 49, 51, 58, 64, ...) = A360403
(3)  v o u' = (5, 8, 12, 18, 21, 28, 32, 35, 39, 46, 50, 53, 59, 62, 67, ...) = A360404
(4)  v' o u' = (2, 6, 15, 27, 34, 45, 55, 60, 69, 81, 91, 96, 108, 114, ...) = A360405
		

Crossrefs

Cf. A026530, A360392, A360393, A360394-A3546352 (intersections instead of results of compositions), A360398-A360401 (results of reversed compositions), A360403, A360404, A360405.

Programs

  • Mathematica
    z = 2000; zz = 100;
    u = Accumulate[1 + ThueMorse /@ Range[0, 600]]; (* A026430 *)
    u1 = Complement[Range[Max[u]], u];  (* A356133 *)
    v = u + 2;  (* A360392 *)
    v1 = Complement[Range[Max[v]], v];  (* A360393 *)
    Table[v[[u[[n]]]], {n, 1, zz}]    (* A360402 *)
    Table[v1[[u[[n]]]], {n, 1, zz}]   (* A360403 *)
    Table[v[[u1[[n]]]], {n, 1, zz}]   (* A360404 *)
    Table[v1[[u1[[n]]]], {n, 1, zz}]  (* A360405 *)
  • Python
    def A360392(n): return n+2+(n-1>>1)+(n-1&1|(n.bit_count()&1^1))
    def A026430(n): return n+(n-1>>1)+(n-1&1|(n.bit_count()&1^1))
    def A360402(n): return A360392(A026430(n)) # Winston de Greef, Mar 24 2023

A360136 a(n) = 1 + A026430(A026430(n)).

Original entry on oeis.org

2, 6, 9, 10, 13, 15, 16, 19, 22, 24, 25, 28, 29, 32, 36, 37, 40, 42, 43, 46, 47, 51, 53, 55, 56, 60, 62, 64, 67, 69, 70, 73, 76, 78, 79, 82, 83, 87, 89, 91, 92, 96, 99, 100, 103, 104, 106, 109, 110, 114, 117, 118, 121, 122, 124, 127, 130, 131, 133, 136, 137
Offset: 1

Views

Author

Clark Kimberling, Feb 03 2023

Keywords

Comments

This is the first of four sequences that partition the positive integers. Suppose that u = (u(n)) and v = (v(n)) are increasing sequences of positive integers. Let u' and v' be their (increasing) complements, and consider these four sequences:
(1) v o u, defined by (v o u)(n) = v(u(n));
(2) v' o u;
(3) v o u';
(4) v' o u.
Every positive integer is in exactly one of the four sequences. Their limiting densities are 4/9, 2/9, 2/9, 1/9, respectively.

Examples

			(1)  v o u = (2, 6, 9, 10, 13, 15, 16, 19, 22, 24, 25, 28, 29, 32, 36, ...) = A360136
(2)  v' o u = (1, 5, 12, 14, 21, 23, 26, 33, 39, 41, 44, 50, 54, 59, 65, ...) = A360137
(3)  v o u' = (4, 7, 11, 17, 20, 27, 31, 34, 38, 45, 49, 52, 58, 61, 66, ...) = A360138
(4)  v' o u' = (3, 8, 18, 30, 35, 48, 57, 63, 72, 84, 93, 98, 111, 116, ...) = A360139
		

Crossrefs

Cf. A026530, A359352, A285953, A359277 (intersections instead of results of composition), A359352-A360135, A360137-A360139.

Programs

  • Mathematica
    z = 2000; zz = 100;
    u = Accumulate[1 + ThueMorse /@ Range[0, 600]]; (* A026430 *)
    u1 = Complement[Range[Max[u]], u];  (* A356133 *)
    v = u + 1;  (* A285954 *)
    v1 = Complement[Range[Max[v]], v];   (* A285953 *)
    Table[v[[u[[n]]]], {n, 1, zz}]       (* A360136 *)
    Table[v1[[u[[n]]]], {n, 1, zz}]      (* A360137 *)
    Table[v[[u1[[n]]]], {n, 1, zz}]      (* A360138 *)
    Table[v1[[u1[[n]]]], {n, 1, zz}]     (* A360139 *)
  • Python
    def A360136(n): return 1+(m:=n+(n-1>>1)+(n-1&1|(n.bit_count()&1^1)))+(m-1>>1)+(m-1&1|(m.bit_count()&1^1)) # Chai Wah Wu, Mar 01 2023

A359353 a(n) = A026430(A285953(n+1)).

Original entry on oeis.org

1, 5, 8, 12, 18, 21, 27, 31, 35, 39, 45, 50, 52, 59, 61, 66, 72, 75, 81, 86, 88, 95, 98, 102, 108, 113, 116, 120, 126, 129, 135, 139, 143, 147, 153, 158, 160, 167, 170, 174, 180, 185, 188, 192, 198, 201, 207, 212, 214, 221, 224, 228, 234, 237, 243, 248, 250
Offset: 1

Views

Author

Clark Kimberling, Jan 30 2023

Keywords

Comments

This is the second of four sequences that partition the positive integers. Suppose that u = (u(n)) and v = (v(n)) are increasing sequences of positive integers. Let u' and v' be their (increasing) complements, and consider these four sequences:
(1) u o v, defined by (u o v)(n) = u(v(n));
(2) u o v';
(3) u' o v;
(4) v' o u'.
Every positive integer is in exactly one of the four sequences. Their limiting densities are 4/9, 2/9, 2/9, 1/9, respectively.

Examples

			(1) u o v = (3, 6, 9, 10, 14, 15, 16, 19, 23, 24, 26, 28, 30, 33, 36, 37, 41, ...) = A359352
(2) u o v' = (1, 5, 8, 12, 18, 21, 27, 31, 35, 39, 45, 50, 52, 59, 61, 66, 72, ...) = A359353
(3) u' o v = (4, 11, 17, 20, 25, 29, 32, 38, 43, 47, 49, 56, 58, 64, 71, 74, ...) = A360134
(4) u' o v' = (2, 7, 13, 22, 34, 40, 53, 62, 67, 76, 89, 97, 104, 115, 122, ...) = A360135
		

Crossrefs

Cf. A026530, A359352, A285953, A285954, A359277 (intersections instead of results of composition), A359352, A360134-A360139.

Programs

  • Mathematica
    z = 2000; zz = 100;
    u = Accumulate[1 + ThueMorse /@ Range[0, 600]]; (* A026430 *)
    u1 = Complement[Range[Max[u]], u];  (* A356133 *)
    v = u + 1;  (* A285954 *)
    v1 = Complement[Range[Max[v]], v];  (* A285953 *)
    Table[u[[v[[n]]]], {n, 1, zz}]      (* A359352 *)
    Table[u[[v1[[n]]]], {n, 1, zz}]     (* A359353 *)
    Table[u1[[v[[n]]]], {n, 1, zz}]     (* A360134 *)
    Table[u1[[v1[[n]]]], {n, 1, zz}]    (* A360135 *)

A360134 a(n) = A356133(1 + A026430(n)).

Original entry on oeis.org

4, 11, 17, 20, 25, 29, 32, 38, 43, 47, 49, 56, 58, 64, 71, 74, 79, 83, 85, 92, 94, 101, 106, 110, 112, 119, 124, 127, 133, 137, 140, 146, 151, 155, 157, 164, 166, 173, 178, 182, 184, 191, 197, 200, 206, 208, 211, 218, 220, 227, 233, 236, 242, 244, 247, 253
Offset: 1

Views

Author

Clark Kimberling, Jan 30 2023

Keywords

Comments

This is the third of four sequences that partition the positive integers. Suppose that u = (u(n)) and v = (v(n)) are increasing sequences of positive integers. Let u' and v' be their (increasing) complements, and consider these four sequences:
(1) u o v, defined by (u o v)(n) = u(v(n));
(2) u o v';
(3) u' o v;
(4) v' o u'.
Every positive integer is in exactly one of the four sequences. Their limiting densities are 4/9, 2/9, 2/9, 1/9, respectively.

Examples

			(1) u o v = (3, 6, 9, 10, 14, 15, 16, 19, 23, 24, 26, 28, 30, 33, 36, 37, 41, ...) = A359352
(2) u o v' = (1, 5, 8, 12, 18, 21, 27, 31, 35, 39, 45, 50, 52, 59, 61, 66, 72, ...) = A359353
(3) u' o v = (4, 11, 17, 20, 25, 29, 32, 38, 43, 47, 49, 56, 58, 64, 71, 74, ...) = A360134
(4) u' o v' = (2, 7, 13, 22, 34, 40, 53, 62, 67, 76, 89, 97, 104, 115, 122, ...) = A360135
		

Crossrefs

Cf. A026530, A359352, A285953, A285954, A359277 (intersections instead of results of composition), A359352, A359353, A360135-A360139.

Programs

  • Mathematica
    z = 2000; zz = 100;
    u = Accumulate[1 + ThueMorse /@ Range[0, 600]]; (* A026430 *)
    u1 = Complement[Range[Max[u]], u];  (* A356133 *)
    v = u + 1;  (* A285954 *)
    v1 = Complement[Range[Max[v]], v];  (* A285953 *)
    Table[u[[v[[n]]]], {n, 1, zz}]      (* A359352 *)
    Table[u[[v1[[n]]]], {n, 1, zz}]     (* A359353 *)
    Table[u1[[v[[n]]]], {n, 1, zz}]     (* A360134 *)
    Table[u1[[v1[[n]]]], {n, 1, zz}]    (* A360135 *)
  • Python
    def A360134(n): return 3*(m:=n+1+(n-1>>1)+(n-1&1|(n.bit_count()&1^1)))-(2 if (m-1).bit_count()&1 else 1) # Chai Wah Wu, Mar 01 2023
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