A046033 a(n) = (n!)^3 - 1.
0, 7, 215, 13823, 1727999, 373247999, 128024063999, 65548320767999, 47784725839871999, 47784725839871999999, 63601470092869631999999, 109903340320478724095999999, 241457638684091756838911999999
Offset: 1
Links
- Vincenzo Librandi, Table of n, a(n) for n = 1..100
- Eric Weisstein's World of Mathematics, Factorial
Crossrefs
Cf. A019514.
Programs
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Magma
[Factorial(n)^3-1: n in [1..15]]; // Vincenzo Librandi, Mar 25 2014
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Maple
seq((n!)^3-1, n=1..20); # Robert Israel, Feb 05 2018
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Mathematica
(Range[20]!)^3-1 (* Harvey P. Dale, Mar 24 2014 *)
Formula
From Robert Israel, Feb 05 2018: (Start)
a(n+1)+1 = (a(n)+1)*(n+1)^3.
-(n^2+5*n+7)*(n+1)^4*a(n)+(n^2+3*n+1)*(n^4+6*n^3+14*n^2+15*n+7)*a(n+1)-n*(n^2+3*n+3)*a(n+2) = 0. (End)