A047270 Numbers that are congruent to {3, 5} mod 6.
3, 5, 9, 11, 15, 17, 21, 23, 27, 29, 33, 35, 39, 41, 45, 47, 51, 53, 57, 59, 63, 65, 69, 71, 75, 77, 81, 83, 87, 89, 93, 95, 99, 101, 105, 107, 111, 113, 117, 119, 123, 125, 129, 131, 135, 137, 141, 143, 147, 149
Offset: 1
Links
- Bruno Berselli, Table of n, a(n) for n = 1..10000 (From _Bruno Berselli_, Jun 24 2010)
- William A. Stein, Dimensions of the spaces S_k(Gamma_0(N)).
- William A. Stein, The modular forms database.
- Index entries for linear recurrences with constant coefficients, signature (1,1,-1).
Crossrefs
Cf. A047235 [(6*n-(-1)^n-3)/2], A047241 [(6*n-(-1)^n-5)/2], A047238 [(6*n-(-1)^n-7)/2]. [Bruno Berselli, Jun 24 2010]
Subsequence of A186422.
From Guenther Schrack, Nov 18 2018: (Start)
Complement: A047237.
First differences: A105397(n) for n > 0.
Partial sums: A227017(n+1) for n > 0.
Elements of odd index: A016945.
Elements of even index: A016969(n-1) for n > 0. (End)
Programs
-
Mathematica
Select[Range@ 149, MemberQ[{3, 5}, Mod[#, 6]] &] (* or *) Array[(6 # - (-1)^# - 1)/2 &, 50] (* or *) Fold[Append[#1, 6 #2 - Last@ #1 - 4] &, {3}, Range[2, 50]] (* or *) CoefficientList[Series[(3 + 2 x + x^2)/((1 + x) (1 - x)^2), {x, 0, 49}], x] (* Michael De Vlieger, Jan 12 2018 *)
-
PARI
a(n) = (6*n - 1 - (-1)^n)/2 \\ David Lovler, Aug 25 2022
Formula
a(n) = sqrt(2)*sqrt((1-6*n)*(-1)^n + 18*n^2 - 6*n + 1)/2. - Paul Barry, May 11 2003
From Bruno Berselli, Jun 24 2010: (Start)
G.f.: (3+2*x+x^2)/((1+x)*(1-x)^2).
a(n) - a(n-1) - a(n-2) + a(n-3) = 0, with n > 3.
a(n) = (6*n - (-1)^n - 1)/2. (End)
a(n) = 6*n - a(n-1) - 4 with n > 1, a(1)=3. - Vincenzo Librandi, Aug 05 2010
From Guenther Schrack, Nov 17 2018: (Start)
a(n) = a(n-2) + 6 for n > 2.
a(-n) = -A047241(n+1) for n > 0.
a(n) = A109613(n-1) + 2*n for n > 0.
a(n) = 2*A001651(n) + 1.
m-element moving averages: Sum_{k=1..m} a(n-m+k)/m = A016777(n-m/2) for m = 2, 4, 6, ... and n >= m. (End)
Sum_{n>=1} (-1)^(n+1)/a(n) = Pi/(4*sqrt(3)) - log(3)/4. - Amiram Eldar, Dec 13 2021
E.g.f.: 1 + 3*x*exp(x) - cosh(x). - David Lovler, Aug 25 2022
Comments