cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

Showing 1-4 of 4 results.

A054678 n consecutive primes differ by a multiple of 4 starting at a(n).

Original entry on oeis.org

7, 89, 199, 463, 463, 463, 11593, 11593, 183091, 241603, 241603, 241603, 9177431, 9177431, 12270077, 105639091, 297779117, 297779117, 727334879, 1113443017, 1113443017, 1113443017, 1113443017, 79263248027, 84676452781, 113391385603
Offset: 2

Views

Author

Jeff Burch, Apr 18 2000

Keywords

Crossrefs

Extensions

More terms from Larry Reeves (larryr(AT)acm.org), Nov 09 2000
More terms from Jens Kruse Andersen, May 29 2006

A276414 Index of the first prime which starts a run of n consecutive primes all congruent to each other mod 3 (or mod 6).

Original entry on oeis.org

1, 9, 15, 54, 271, 271, 2209, 11199, 13717, 13717, 34369, 136456, 172146, 1254203, 1254203, 4308948, 12762142, 21357253, 25813464, 25813464, 39500857, 39500857, 947438659, 947438659, 947438659, 5703167678, 5703167678, 16976360924, 57446769091, 57446769091, 57446769091
Offset: 1

Views

Author

M. F. Hasler, Sep 02 2016

Keywords

Comments

First term of runs of increasing length of consecutive integers in A270190. - M. F. Hasler, Sep 03 2016

Examples

			prime(9) = 23 starts the first run of 2 consecutive primes, {23, 29}, which are congruent to each other (mod 6). Therefore a(2) = 9.
prime(15) = 47 starts the first run of 3 consecutive primes, {47, 53, 59}, which are congruent to each other (mod 6). Therefore a(3) = 15.
prime(54) = 251 starts the first run of 4 consecutive primes, {251, 257, 263, 269}, which are congruent to each other (mod 6). Therefore a(4) = 54.
prime(271) = 1741 starts the first run of 5 consecutive primes, {1741, 1747, 1753, 1759, 1777}, which are congruent to each other (mod 6). Therefore a(5) = 271. This is the first case where the primes are of the form 3k+1.
prime(271) = 1741 also starts the first run of 6 consecutive primes, {1741, 1747, 1753, 1759, 1777, 1783}, which are all congruent to each other (mod 6). Therefore a(6) = 271, too.
		

Crossrefs

Subsequence of A270190 (after discarding 1 and duplicates of other terms).

Programs

  • PARI
    m=c=i=o=0;print1(1);forprime(p=1,,i++;(o-o=p)%3&&(!c||!c=0)&&next;c++>m||next;print1(",",i-m=c))

Formula

a(n) = A000720(A054679(n)).

Extensions

a(30)-a(31) from and name clarified by Jinyuan Wang, Feb 24 2020

A054680 n consecutive primes differ by a multiple of 8 starting at a(n).

Original entry on oeis.org

89, 1823, 20809, 73133, 989647, 3250469, 9065867, 35677501, 101341613, 1383423311, 11312238283, 19201563659, 132932904029, 534956098463, 925195153703, 20151469541389, 20151469541389, 102573904861013
Offset: 2

Views

Author

Jeff Burch, Apr 18 2000

Keywords

Crossrefs

Extensions

More terms from Larry Reeves (larryr(AT)acm.org), Nov 09 2000
More terms from Larry Soule (lsoule(AT)gmail.com), Jun 11 2006
a(17)-a(19) from Giovanni Resta, Aug 02 2013

A259360 Initial prime in the least set of exactly n+1 consecutive primes with n gaps all multiples of 4.

Original entry on oeis.org

7, 89, 199, 883, 12401, 463, 36551, 11593, 183091, 766261, 3358169, 241603, 11739307, 9177431, 12270077, 105639091, 310523021, 297779117, 727334879, 5344989829, 1481666377, 2572421893, 1113443017, 79263248027, 84676452781
Offset: 1

Views

Author

Zak Seidov, Jun 24 2015

Keywords

Examples

			a(6)=463 because the first set of 7 consecutive primes is {463,467,479,487,491,499,503} with 6 gaps {4,12,8,4,8,4} all multiples of 4 while the next prime after 503 is 509 and 509-503=6 is not a multiple of 4.
		

Crossrefs

Programs

  • PARI
    back(p,n)=while(n,p=precprime(p-1); n--); p
    v=vector(20); g=0; p=2; forprime(q=3,1e6, if((q-p)%4, if(g&&g<=#v&&v[g]==0, v[g]=back(p,g)); g=0, g++);p=q); v \\ Charles R Greathouse IV, Jul 14 2015

Extensions

a(13)-a(14) corrected by Charles R Greathouse IV, Jul 14 2015
a(24)-a(25) by Zak Seidov, Jul 15 2015
Showing 1-4 of 4 results.