A055482 There exists some k>0 such that n is the product of (k + digits of n).
12, 18, 24, 35, 50, 56, 90, 120, 210, 315, 450, 780, 840, 1500, 3920, 4320, 4752, 7744, 16500, 24960, 57915, 59400, 60480, 91728, 269500, 493920, 917280, 1293600, 2419200, 3386880, 34992000, 266378112, 317447424, 1277337600, 3714984000, 14948388000, 48697248600, 460522782720, 896168448000
Offset: 1
Examples
4752 = (4+4)(4+7)(4+5)(4+2).
Links
- Giovanni Resta, Table of n, a(n) for n = 1..59 (terms < 10^38)
Crossrefs
Programs
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Mathematica
L={}; Do[Print@ n; Do[p = Reverse/@ IntegerPartitions[ k, {n}, Range[0, 9]]; Do[z = Times@@ (e + k); If[ Sort@ IntegerDigits@ z == e, Print[{z, k}]; AppendTo[L, z]], {k, 9}, {e, p}], {k, 9*n}],{n, 2, 13}]; Sort@ L (* terms < 10^13, Giovanni Resta, Jul 24 2015 *)
Extensions
Offset corrected and more terms added by Max Alekseyev, Jan 23 2015
Comments