A063086 a(n) = gcd(1 + prime(n+1), 1 + prime(n)).
1, 2, 2, 4, 2, 2, 2, 4, 6, 2, 2, 2, 2, 4, 6, 6, 2, 2, 4, 2, 2, 4, 6, 2, 2, 2, 4, 2, 2, 2, 4, 6, 2, 10, 2, 2, 2, 4, 6, 6, 2, 2, 2, 2, 2, 4, 4, 4, 2, 2, 6, 2, 2, 6, 6, 6, 2, 2, 2, 2, 2, 14, 4, 2, 2, 2, 2, 2, 2, 2, 6, 8, 2, 2, 4, 6, 2, 2, 2, 10, 2, 2, 2, 2, 4, 6, 2, 2, 2, 4, 12, 8, 4, 4, 4, 6, 6, 2, 2, 2, 2, 6
Offset: 1
Examples
n=34: gcd(1 + 139, 1 + 149) = 10 = a(34).
Links
- Harry J. Smith, Table of n, a(n) for n = 1..1000
Crossrefs
Cf. A058263.
Programs
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Mathematica
GCD[First[#]+1,Last[#]+1]&/@ Partition[Prime[Range[110]],2,1] (* Harvey P. Dale, May 02 2012 *)
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PARI
a(n)={gcd(1 + prime(n+1), 1 + prime(n))} \\ Harry J. Smith, Aug 17 2009