A065409 Fennessey-Larcombe-French sequence.
1, 8, 144, 2432, 40000, 649728, 10486784, 168681472, 2708038656, 43425996800, 695894425600, 11146676797440, 178493059563520, 2857665426882560, 45744737668300800, 732196083173687296, 11718755500209471488
Offset: 0
References
- A. F. Jarvis, P. J. Larcombe and D. R. French, Linear recurrences between two recent integer sequences, Congressus Numerantium, 169 (2004), 79-99.
- A. F. Jarvis, P. J. Larcombe and D. R. French, Power series identities generated by two recent integer sequences, Bulletin ICA, 43 (2005), 85-95.
- P. J. Larcombe, A new asymptotic relation between two recent integer sequences, Congressus Numerantium, 175 (2005), 111-116.
- P. J. Larcombe, D. R. French and E. J. Fennessey, The Fennessey-Larcombe-French sequence {1, 8, 144, 2432, 40000, ...}: formulation and asymptotic form, Congressus Numerantium, 158 (2002), 179-190.
- P. J. Larcombe, D. R. French and E. J. Fennessey, The Fennessey-Larcombe-French sequence {1, 8, 144, 2432, 40000, ...}: a recursive formulation and prime factor decomposition, Congressus Numerantium, 160 (2003), 129-137.
Links
- T. D. Noe, Table of n, a(n) for n=0..200
- Arthur L. B. Yang, James J. Y. Zhao, Log-concavity of the Fennessey-Larcombe-French Sequence, arXiv:1503.02151 [math.CO], 2015.
Programs
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Mathematica
a[n_] := 8^n*HypergeometricPFQ[{1/2, 5/4, 1/2-n/2, -n/2}, {1/4, 1, 1}, 1 ]; Table[ a[n], {n, 0, 16}] (* Jean-François Alcover, Jan 31 2012, from first formula *) Table[2^n Sum[(4k^2-2k-1)/(2k-1) Binomial[n,k]Binomial[2n-2k,n-k] Binomial[ 2k,k],{k,0,n}],{n,0,20}] (* Harvey P. Dale, Mar 18 2012 *) a[ n_] := If[ n < 0, 0, SeriesCoefficient[ Sum[ Binomial[2 k, k]^2 / (1 - 2 k) (2 x - 16 x^2)^k, {k, 0, n}] / (1 - 16 x), {x, 0, n}]]; (*Michael Somos, Jul 10 2017 *) a[ n_] := If [n < 0, 0, n! SeriesCoefficient[ Exp[8 x] BesselI[0, 4 x] (BesselI[0, 4 x] + 16 x BesselI[1, 4 x]), {x, 0, n}]]; (* Michael Somos, Jul 10 2017 *)
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PARI
{a(n) = my(A); if( n<0, 0, A =a gm(1, 1 - 16*x + x*O(x^n)); polcoeff((1 - 16*x - 2*x*(1 - 8*x) * log(A)') / A, n))}; /* Michael Somos, Mar 04 2003 */
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PARI
{a(n) = if( n<0, 0, polcoeff( sum(k=0, n, binomial(2*k,k)^2 / (1 - 2*k) * (2*x - 16*x^2)^k, x*O(x^n)) / (1 - 16*x), n))}; /* Michael Somos, Mar 04 2003 */
Formula
a(n) = 8^n * 4F3( [5/4, 1/2, (1/2)-n/2, -n/2], [1, 1, 1/4] | 1 ).
G.f.: F(-1/2, 1/2; 1; 32*x - 256*x^2) / (1 - 16*x) = E'(1 - 16*x) / (Pi/2 * (1 - 16*x)). - Michael Somos, Mar 04 2003
a(n)*(n^3 - n^2) = a(n-1)*(8 - 32*n^2 + 24*n^3) + a(n-2)*(256*n^2 - 128*n^3). - Michael Somos, Mar 04 2003
a(n) = 2^n*Sum_{k=0..n} (4*k^2-2*k-1)/(2*k-1)*binomial(n, k)*binomial(2*n-2*k, n-k)*binomial(2*k, k). - Vladeta Jovovic, Jun 02 2005
E.g.f.: exp(8*x)*BesselI(0, 4*x)*(BesselI(0, 4*x)+16*x*BesselI(1, 4*x)). - Vladeta Jovovic, Jun 02 2005
a(n) ~ 2^(4*n+1)/Pi. - Vaclav Kotesovec, Aug 13 2013
Comments