A068579 Let phi_m(x) = phi(phi(...(phi(x))...)) m times; sequence gives values of k such that phi_3(k) = tau(k).
1, 11, 13, 19, 33, 34, 35, 39, 46, 57, 58, 62, 74, 86, 88, 102, 104, 105, 110, 130, 135, 138, 152, 154, 174, 182, 186, 190, 222, 258, 264, 280, 312, 330, 342, 390, 456, 462, 546, 570, 594, 756, 840, 1080
Offset: 1
Programs
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Mathematica
Select[Range[1080], Nest[EulerPhi, #, 3] === DivisorSigma[0, #] &] (* Amiram Eldar, Jun 12 2022 *)
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PARI
is(k) = numdiv(k) == eulerphi(eulerphi(eulerphi(k))); \\ Jinyuan Wang, Apr 05 2020
Comments