cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

Showing 1-4 of 4 results.

A069040 Numbers k that divide the numerator of B(2k) (the Bernoulli numbers).

Original entry on oeis.org

1, 5, 7, 11, 13, 17, 19, 23, 25, 29, 31, 35, 37, 41, 43, 47, 49, 53, 59, 61, 65, 67, 71, 73, 77, 79, 83, 85, 89, 91, 95, 97, 101, 103, 107, 109, 113, 115, 119, 121, 125, 127, 131, 133, 137, 139, 143, 145, 149, 151, 155, 157, 161, 163, 167, 169, 173, 175, 179, 181
Offset: 1

Views

Author

Benoit Cloitre, Apr 03 2002

Keywords

Comments

Equivalently, k is relatively prime to the denominator of B(2k). Equivalently, there are no primes p such that p divides k and p-1 divides 2k. These equivalences follow from the von Staudt-Clausen and Sylvester-Lipschitz theorems.
The listed terms are the same as those in A070191, but the sequences are not identical. (The similarity is mostly explained by the absence of multiples of 2, 3 and 55 from both sequences.) See A070192 and A070193 for the differences.

References

  • G. H. Hardy and E. M. Wright, An Introduction to the Theory of Numbers, 3rd ed., Oxford Univ. Press, 1954.

Crossrefs

Programs

  • Maple
    A069040 := proc(n)
        option remember;
        if n=1 then
            1;
        else
            for k from procname(n-1)+1 do
                if numer(bernoulli(2*k)) mod k = 0 then
                    return k;
                end if;
            end do:
        end if;
    end proc: # R. J. Mathar, Jan 06 2013
  • Mathematica
    testb[n_] := Select[First/@FactorInteger[n], Mod[2n, #-1]==0&]=={}; Select[Range[200], testb]
  • PARI
    isok(k) = {my(p = factor(k)[,1]); for(i = 1, #p, if(!((2*k) % (p[i]-1)), return(0))); 1;} \\ Amiram Eldar, Apr 24 2025

Extensions

More information from Dean Hickerson, Apr 26 2002

A070193 Numbers k such that gcd(3k,8^k+1) = 3 but k does not divide the numerator of B(2k) (the Bernoulli numbers).

Original entry on oeis.org

253, 1081, 1771, 2485, 2783, 3289, 4301, 4807, 5405, 5819, 7337, 7567, 7843, 9361, 10373, 10879, 11891, 12397, 12425, 13409, 13861, 14053, 14927, 15433, 17395, 17963, 18145, 18377, 18469, 19481, 19987, 20539, 20999, 22517, 23023, 24541
Offset: 1

Views

Author

Benoit Cloitre and Dean Hickerson, Apr 26 2002

Keywords

Comments

Equivalently, numbers is in A070191 but not in A069040.

Crossrefs

Programs

  • Mathematica
    testb[n_] := Select[First/@FactorInteger[n], Mod[2n, #-1]==0&]=={}; test8[n_] := GCD[3n, PowerMod[8, n, 3n]+1]==3; Select[Range[25000], test8[ # ]&&!testb[ # ]&]
  • PARI
    isA070191(k) = gcd(3*k, Mod(8, 3*k)^k + 1) == 3;
    isok(k) = if(!isA070191(k), 0, my(p = factor(k)[,1]); for(i = 1, #p, if(!((2*k) % (p[i]-1)), return(1))); 0); \\ Amiram Eldar, Apr 24 2025

A070191 Numbers k such that gcd(3*k, 8^k+1) = 3.

Original entry on oeis.org

1, 5, 7, 11, 13, 17, 19, 23, 25, 29, 31, 35, 37, 41, 43, 47, 49, 53, 59, 61, 65, 67, 71, 73, 77, 79, 83, 85, 89, 91, 95, 97, 101, 103, 107, 109, 113, 115, 119, 121, 125, 127, 131, 133, 137, 139, 143, 145, 149, 151, 155, 157, 161, 163, 167, 169, 173, 175, 179, 181
Offset: 1

Views

Author

Benoit Cloitre and Dean Hickerson, Apr 26 2002

Keywords

Comments

The listed terms are the same as those in A069040, but the sequences are not identical. (The similarity is mostly explained by the absence of multiples of 2, 3 and 55 from both sequences.) See A070192 and A070193 for the differences.
The number of terms not exceeding 10^m, for m = 1, 2, ..., are 3, 32, 325, 3244, 32468, 324667, 3246642, 32466291, 324662816, 3246627133, ... . Apparently, the asymptotic density of this sequence exists and equals 0.32466... . - Amiram Eldar, Jun 14 2022

Crossrefs

Programs

  • Mathematica
    test8[n_] := GCD[3n, PowerMod[8, n, 3n]+1]==3; Select[Range[200], test8]

A281648 (Numerator of Bernoulli(2*n)) read mod n.

Original entry on oeis.org

0, 1, 1, 3, 0, 5, 0, 7, 1, 9, 0, 5, 0, 7, 5, 15, 0, 11, 0, 9, 1, 11, 0, 13, 0, 13, 19, 7, 0, 19, 0, 31, 11, 17, 0, 11, 0, 19, 13, 13, 0, 37, 0, 33, 35, 23, 0, 37, 0, 39, 34, 39, 0, 11, 5, 35, 19, 29, 0, 29, 0, 31, 61, 63, 0, 55, 0, 51, 23, 21, 0, 43, 0, 37, 50, 19
Offset: 1

Views

Author

Seiichi Manyama, Jan 26 2017

Keywords

Comments

Conjecture: a(n) == n-1 (mod n) if only if n = 6, 10 or n = 2^k for k >= 0. This is true for n <= 1024. - Seiichi Manyama, Jan 27 2017

Crossrefs

Programs

  • Mathematica
    f[n_] := Mod[Numerator[BernoulliB[2 n]], n]; Array[f, 77] (* Robert G. Wilson v, Jan 26 2017 *)
  • PARI
    a(n)=numerator(bernfrac(2*n))%n \\ Charles R Greathouse IV, Jan 27 2017
  • Ruby
    def bernoulli(n)
      ary = []
      a = []
      (0..n).each{|i|
        a << 1r / (i + 1)
        i.downto(1){|j| a[j - 1] = j * (a[j - 1] - a[j])}
        ary << a[0]
      }
      ary
    end
    def A281648(n)
      a = bernoulli(2 * n)
      (1..n).map{|i| a[2 * i].numerator % i}
    end
    

Formula

a(n) = A000367(n) mod n.
Showing 1-4 of 4 results.