A077059 Numbers j such that j^2 + k^2 is a cube for some k > j.
0, 2, 5, 7, 9, 10, 16, 17, 18, 26, 30, 35, 36, 37, 38, 40, 44, 47, 50, 51, 54, 56, 58, 60, 65, 72, 73, 74, 75, 80, 82, 88, 95, 97, 101, 102, 106, 107, 115, 122, 128, 130, 135, 136, 140, 142, 143, 144, 145, 146, 150, 154, 164, 170, 174, 182, 187, 189, 190
Offset: 1
Keywords
Examples
2 is in the sequence because 2^2 + 11^2 = 5^3; 7 is in the sequence because 7^2 + 524^2 = 65^3; 1 is not in the sequence because 1^2 + k^2 is not a cube for any k > 1; 3 is not in the sequence because 3^2 + k^2 is not a cube for any k > 3. 174 is in the sequence because 174^2 + 406^2 = 58^3. - _Sean A. Irvine_, May 02 2025
Formula
j is in this sequence if for some integer k > j, j^2 + k^2 = c^3.
Extensions
Corrected and extended by Max Alekseyev, Dec 14 2011
Missing 174 inserted by Sean A. Irvine, May 02 2025
Comments