A082511 a(n) = 3^n mod 2n.
1, 1, 3, 1, 3, 9, 3, 1, 9, 9, 3, 9, 3, 9, 27, 1, 3, 9, 3, 1, 27, 9, 3, 33, 43, 9, 27, 25, 3, 9, 3, 1, 27, 9, 47, 9, 3, 9, 27, 1, 3, 57, 3, 81, 63, 9, 3, 33, 31, 49, 27, 81, 3, 81, 67, 65, 27, 9, 3, 81, 3, 9, 27, 1, 113, 69, 3, 81, 27, 109, 3, 81, 3, 9, 57, 81, 75, 105, 3, 1, 81, 9, 3, 57, 73
Offset: 1
Keywords
Examples
Residues are often also powers of 3, that is, 3^n = k*2*n + 3^j, as is the case for n=1..23. The first terms that are not powers of 3 are a(24)=33 and a(25)=43. a(6)=9: modulus = 2*n = 12; 3^n = 3^6 = 729 = 60*12 + 9 = 720 + a(6).
Links
- Vincenzo Librandi, Table of n, a(n) for n = 1..2000
Programs
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Mathematica
Table[PowerMod[3,n,2n],{n,90}] (* Harvey P. Dale, Jan 21 2014 *)
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PARI
a(n) = lift(Mod(3, 2*n)^n) \\ Felix Fröhlich, Oct 20 2018
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Python
for n in range(1, 80): print(pow(3, n, 2*n), end=" ") # Stefano Spezia, Oct 20 2018