cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

Showing 1-3 of 3 results.

A085012 For p = prime(n), a(n) is the smallest prime q such that pq is a base-2 pseudoprime; that is, 2^(pq-1) = 1 mod pq; a(n) is 0 if no such prime exists.

Original entry on oeis.org

0, 0, 0, 31, 0, 257, 73, 89, 113, 11, 73, 61681, 127, 178481, 157, 233, 1321, 20857, 281, 19, 2731, 13367, 23, 193, 601, 307, 6361, 37, 29, 43, 2731, 953, 168749965921, 593, 31, 53, 2593, 499, 101653, 62020897, 54001, 2281, 97, 19707683773, 5347, 29191
Offset: 2

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Author

T. D. Noe, Jun 28 2003

Keywords

Comments

Using a construction in Erdős's paper, it can be shown that every odd prime except 3, 5, 7 and 13 is a factor of some 2-factor pseudoprime. Note that the cofactor q can be very large; for p=317, the smallest is 381364611866507317969. Using a theorem of Lehmer, it can be shown that the possible values of q are among the prime factors of 2^(p-1)-1. The sequence A085014 gives the number of 2-factor pseudoprimes that have prime(n) as a factor.
Sequence A086019 gives the largest prime q such that q*prime(n) is a pseudoprime.

Examples

			a(11) = 11 because prime(11) = 31 and 11 is the smallest factor of 2^30-1 that yields a pseudoprime when multiplied by 31.
		

References

  • Paulo Ribenboim, The New Book of Prime Number Records, Springer, 1996, p. 105-112.

Crossrefs

Cf. A001567 (base-2 pseudoprimes), A085014, A086019, A180471.

Programs

  • Mathematica
    Table[p=Prime[n]; q=Transpose[FactorInteger[2^(p-1)-1]][[1]]; i=1; While[i<=Length[q] && (PowerMod[2, p*q[[i]]-1, p*q[[i]]]>1), i++ ]; If[i>Length[q], 0, q[[i]]], {n, 2, 56}]

A085014 For p = prime(n), a(n) is the number of primes q such that pq is a base-2 pseudoprime; that is, 2^(pq-1) = 1 mod pq.

Original entry on oeis.org

0, 0, 0, 1, 0, 1, 1, 2, 1, 3, 2, 1, 3, 2, 2, 4, 1, 2, 3, 5, 4, 3, 6, 4, 4, 6, 4, 5, 4, 6, 5, 4, 2, 5, 8, 7, 5, 6, 3, 3, 3, 4, 5, 4, 4, 5, 9, 8, 7, 8, 5, 8, 7, 8, 4, 6, 6, 7, 7, 9, 6, 11, 7, 8, 2, 7, 12, 8, 6, 8, 4, 5, 5, 6, 5, 11, 10, 9, 11, 5, 8, 9, 12, 9, 4, 7, 13, 8, 5
Offset: 2

Views

Author

T. D. Noe, Jun 28 2003

Keywords

Comments

Using a construction in Erdős's paper, it can be shown that a(prime(n)) > 0, except for the primes 3, 5, 7 and 13. Using a theorem of Lehmer, it can be shown that the possible values of q are among the prime factors of 2^(p-1)-1. The sequence A085012 gives the smallest prime q such that q*prime(n) is a pseudoprime.
Sequence A086019 gives the largest prime q such that q*prime(n) is a pseudoprime.

Examples

			a(11) = 3 because prime(11) = 31 and 2^30-1 has 3 prime factors (11, 151, 331) that yield pseudoprimes when multiplied by 31.
		

References

  • Paulo Ribenboim, The New Book of Prime Number Records, Springer, 1996, p. 105-112.

Crossrefs

Cf. A001567 (base-2 pseudoprimes), A085012, A086019, A180471.

Programs

  • Mathematica
    Table[p=Prime[n]; q=Transpose[FactorInteger[2^(p-1)-1]][[1]]; cnt=0; Do[If[PowerMod[2, p*q[[i]]-1, p*q[[i]]]==1, cnt++ ], {i, Length[q]}]; cnt, {n, 2, 50}]

Formula

a(n) < 0.7 * p, where p is the n-th prime. - Charles R Greathouse IV, Apr 12 2012

A358699 a(n) is the largest prime factor of 2^(prime(n) - 1) - 1.

Original entry on oeis.org

3, 5, 7, 31, 13, 257, 73, 683, 127, 331, 109, 61681, 5419, 2796203, 8191, 3033169, 1321, 599479, 122921, 38737, 22366891, 8831418697, 2931542417, 22253377, 268501, 131071, 28059810762433, 279073, 54410972897, 77158673929, 145295143558111, 2879347902817, 10052678938039
Offset: 2

Views

Author

Hugo Pfoertner, Nov 27 2022

Keywords

Crossrefs

Subsequence of A005420 and of A274906.

Programs

  • PARI
    forprime (p=3, 140, my(f=factor(2^(p-1)-1)); print1(f[#f[,1],1],", "))
    
  • Python
    from sympy import primefactors, sieve
    def A358699(n): return primefactors(2**(sieve[n]-1)-1)[-1] # Karl-Heinz Hofmann, Nov 28 2022

Formula

a(n) = A006530(A098102(n)). - Michel Marcus, Nov 28 2022
a(n) = A005420(A006093(n)). - Amiram Eldar, Dec 01 2022
Showing 1-3 of 3 results.