cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

Showing 1-2 of 2 results.

A071963 Largest prime factor of p(n), the n-th partition number A000041(n) (with a(0) = a(1) = 1 by convention).

Original entry on oeis.org

1, 1, 2, 3, 5, 7, 11, 5, 11, 5, 7, 7, 11, 101, 5, 11, 11, 11, 11, 7, 19, 11, 167, 251, 7, 89, 29, 43, 13, 83, 467, 311, 23, 23, 1231, 41, 17977, 281, 43, 11, 127, 193, 2417, 71, 97, 1087, 241, 67, 7013, 631, 9283, 661, 53, 5237, 59, 227, 1019, 102359, 3251, 199, 409, 971
Offset: 0

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Author

Benoit Cloitre, Jun 16 2002

Keywords

Comments

Cilleruelo and Luca prove that a(n) > log log n, for almost all n.
By computation, a(n) > log n, at least up to n = 2500. In fact, a(n) > n if n > 39, at least up to n = 2500; see A192885. - Jonathan Sondow, Aug 16 2011

Examples

			A000041(110) = 607163746 = 2*7*4049*10711, therefore a(110)=10711. - _Reinhard Zumkeller_, Aug 23 2003
		

Crossrefs

Programs

  • Mathematica
    Table[First[Last[FactorInteger[PartitionsP[n]]]], {n, 0, 100}] (* Jonathan Sondow, Aug 16 2011 *)
  • PARI
    for(n=2,75,print1(vecmax(component(factor(polcoeff(1/eta(x),n,x)),1)),","))
    
  • PARI
    a(n)=local(v); if(n<2,n>=0,v=factor(polcoeff(1/eta(x+x*O(x^n)),n))~[1,]; v[ #v])
    
  • PARI
    a(n)=if(n<2,1,factor(numbpart(n))[1,1]) \\ Charles R Greathouse IV, May 29 2015

Formula

a(n) = A006530(A000041(n)).

Extensions

Corrected by T. D. Noe, Nov 15 2006
Edited by N. J. A. Sloane, Oct 27 2008 at the suggestion of R. J. Mathar
a(0) = 1 added by N. J. A. Sloane, Sep 13 2009

A194345 Numbers k for which the largest prime factor of p(k) divides p(1)*p(2)*...*p(k-1), where p(k) is the number of partitions of k.

Original entry on oeis.org

1, 7, 8, 9, 10, 11, 12, 14, 15, 16, 17, 18, 19, 21, 24, 33, 38, 39, 82, 97, 158, 166, 180
Offset: 1

Views

Author

Jonathan Sondow, Aug 21 2011

Keywords

Comments

It appears that for all k > 180, the largest prime factor of p(k) does not divide p(1)*p(2)*...*p(k-1). This has been checked up to k = 2000. [Checked up to k = 10000, using A071963 b-file. - Pontus von Brömssen, Jun 05 2023]
See A071963 and A194259 for links and additional comments.

Examples

			1 is in the sequence because p(1) = 1 and 1 has no prime factor, so the condition is vacuously true.
For k = 7, 8, 9, 10, 11, 12, 14, 15, 16, 17, 18, 19, 21, 24, 33, 38, 39, 82, 97, every prime factor of p(k) divides p(1)*p(2)*...*p(k-1).
For k = 158, 166, 180, not every prime factor of p(k) divides p(1)*p(2)*...*p(k-1), but the largest one does.
		

Crossrefs

Showing 1-2 of 2 results.