cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

Showing 1-7 of 7 results.

A069513 Characteristic function of the prime powers p^k, k >= 1.

Original entry on oeis.org

0, 1, 1, 1, 1, 0, 1, 1, 1, 0, 1, 0, 1, 0, 0, 1, 1, 0, 1, 0, 0, 0, 1, 0, 1, 0, 1, 0, 1, 0, 1, 1, 0, 0, 0, 0, 1, 0, 0, 0, 1, 0, 1, 0, 0, 0, 1, 0, 1, 0, 0, 0, 1, 0, 0, 0, 0, 0, 1, 0, 1, 0, 0, 1, 0, 0, 1, 0, 0, 0, 1, 0, 1, 0, 0, 0, 0, 0, 1, 0, 1, 0, 1, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0
Offset: 1

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Author

Benoit Cloitre, Apr 15 2002

Keywords

Comments

Also, number of Galois fields of order n. - Charles R Greathouse IV, Mar 12 2008
Also, number of abelian indecomposable groups of order n. - Kevin Lamoreau, Mar 13 2023

Crossrefs

The partial sums of this sequence give A025528. - Daniel Forgues, Mar 02 2009

Programs

Formula

If n >= 2, a(n) = A010055(n).
a(n) = Sum_{d|n} bigomega(d)*mu(n/d); equivalently, Sum_{d|n} a(d) = bigomega(n); equivalently, Möbius transform of bigomega(n).
Dirichlet g.f.: ppzeta(s). Here ppzeta(s) = Sum_{p prime} Sum_{k>=1} 1/(p^k)^s. Note that ppzeta(s) = Sum_{p prime} 1/(p^s - 1) = Sum_{k>=1} primezeta(k*s). - Franklin T. Adams-Watters, Sep 11 2005
a(n) = floor(1/A001221(n)), for n > 1. - Enrique Pérez Herrero, Jun 01 2011
a(n) = - Sum_{d|n} mu(d)*bigomega(d), where bigomega = A001222. - Ridouane Oudra, Oct 29 2024
a(n) = - Sum_{d|n} mu(d)*omega(d), where omega = A001221. - Ridouane Oudra, Jul 30 2025

Extensions

Moved original definition to formula line. Used comment (that I previously added) as definition. - Daniel Forgues, Mar 08 2009
Edited by Franklin T. Adams-Watters, Nov 02 2009

A338757 Number of splitting-simple groups of order n; number of nontrivial groups of order n that are not semidirect products of proper subgroups.

Original entry on oeis.org

0, 1, 1, 1, 1, 0, 1, 2, 1, 0, 1, 0, 1, 0, 0, 2, 1, 0, 1, 0, 0, 0, 1, 0, 1, 0, 1, 0, 1, 0, 1, 5, 0, 0, 0, 0, 1, 0, 0, 0, 1, 0, 1, 0, 0, 0, 1, 1, 1, 0, 0, 0, 1, 0, 0, 0, 0, 0, 1, 1, 1, 0, 0, 19, 0, 0, 1, 0, 0, 0, 1, 0, 1, 0, 0, 0, 0, 0, 1, 0, 2, 0, 1, 0, 0, 0, 0, 0, 1
Offset: 1

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Author

Jianing Song, Nov 07 2020

Keywords

Comments

The other names for groups of this kind include "semidirectly indecomposable groups" or "inseparable groups". Note that the following are equivalent definitions for a nontrivial group to be a splitting-simple group:
- It is not the (internal) semidirect product of proper subgroups;
- It is not isomorphic to the (external) semidirect product of nontrivial groups;
- It has no proper nontrivial normal subgroups with a permutable complement.
- It is the non-split extension of every proper nontrivial normal subgroup by the corresponding quotient group.
Also note that being simple is a stronger condition than being splitting-simple, while being directly indecomposable (see A090751) is weaker.
a(p^e) >= 1 since C_p^e cannot be written as the semidirect product of proper subgroups. For e >= 3, a(2^e) >= 2 by the existence of the generalized quaternion group of order 2^e, which is the only non-split extension of C_2^(e-1) by C_2 other than C_2^e.
The smallest numbers here with a(n) > 0 that are not prime powers are 48, 60, 120, 144, 168, 192, 240, 320, 336, 360 and so on. Are there any odd numbers n that are not prime powers satisfying a(n) > 0 ?
Conjecture: a(n) = 0 for squarefree n which is not a prime.
The conjecture that a(n) = 0 for nonprime squarefree n is true. Proof: It is known that every group G of squarefree order is supersolvable; hence G contains a normal series with prime cyclic factors. Since every Sylow subgroup of G is prime cyclic, these cyclic factors are isomorphic to the Sylow subgroups of G. Let P be one such factor; then for an appropriate M in G, P = G/M, where |G| = |P|*|M|. By the Schur-Zassenhaus theorem, G is a semidirect product of M and P, and a(n) = 0 when n is squarefree. - Miles Englezou, Oct 24 2024

Examples

			a(48) = 1 because the binary octahedral group, which is of order 48, cannot be written as the semidirect product of proper subgroups.
a(16) = 2, and the corresponding groups are C_16 and Q_16 (generalized quaternion group of order 16).
a(81) = 2, and the corresponding groups are C_81 and SmallGroup(81,10).
a(64) = 19, and the corresponding groups are SmallGroup(64,i) for i = 1, 11, 13, 14, 19, 22, 37, 43, 45, 49, 54, 79, 81, 82, 160, 168, 172, 180 and 245.
For n = 60 or 168, the unique simple group is the only group of order n that cannot be written as the semidirect product of proper subgroups, hence a(60) = a(168) = 1. [The unique simple groups are respectively Alt(5) and PSL(2,7). - _Bernard Schott_, Nov 08 2020]
For n = 12, we have C_12 = C_3 X C_4, C_6 X C_2 = C_6 X C_2, D_6 = C_6 : C_2, Dic_12 = C_3 : C_4 and A_4 = (C_2 X C_2) : C_3, all of which can be written as the semidirect product of nontrivial groups. So a(12) = 0.
		

Crossrefs

Cf. A000001, A090751 (number of directly indecomposable groups of order n), A001034, A120944.

Programs

  • GAP
    IsSplittingSimple := function(G)
      local c, l, i;
      c := NormalSubgroups(G);
      l := Length(c);
      if l > 1 then
        for i in [2..l-1] do
        if Length(ComplementClassesRepresentatives(G,c[i])) > 0 then
          return false;
        fi;
        od;
        return true;
      else
        return false;
      fi;
    end;
    A338757 := n -> Length(AllSmallGroups( n, IsSplittingSimple ));

Formula

For primes p != q:
a(p) = a(p^2) = 1; a(p^3) = 2 for p = 2, 1 otherwise;
a(p^4) = 2 for p = 2 or 3, 1 otherwise;
a(pq) = 0;
a(4p) = a(8p) = 0, p > 2.
a(n) <= A090751(n) for all n, and the equality holds if n = 1, p, p^2 for primes p or n = pq for primes p < q and p does not divide q-1.
a(A001034(k)) >= 1, since A001034 lists the orders of (non-Abelian) simple groups.
a(A120944(n)) = 0. - Miles Englezou, Oct 24 2024

A361414 Number of non-abelian indecomposable groups of order n.

Original entry on oeis.org

0, 0, 0, 0, 0, 1, 0, 2, 0, 1, 0, 2, 0, 1, 0, 7, 0, 2, 0, 2, 1, 1, 0, 6, 0, 1, 2, 1, 0, 1, 0, 33, 0, 1, 0, 4, 0, 1, 1, 5, 0, 2, 0, 1, 0, 1, 0, 23, 0, 2, 0, 2, 0, 6, 1, 5, 1, 1, 0, 3, 0, 1, 1, 200, 0, 1, 0, 2, 0, 1, 0, 19, 0, 1, 1, 1, 0, 2, 0, 24, 8, 1, 0, 3, 0
Offset: 1

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Author

Kevin Lamoreau, Mar 10 2023

Keywords

Examples

			a(16) = 7 because 1 of the 8 indecomposable groups of order 16 is abelian and 2 of the 9 non-abelian groups of order 16 are decomposable, leaving 7 non-abelian indecomposable groups of order 16.
		

Crossrefs

Formula

a(n) = A090751(n) - A069513(n).

A094448 Number of indecomposable groups of order 2^n.

Original entry on oeis.org

0, 1, 1, 3, 8, 34, 201, 2000, 53410, 10435175, 49476809194
Offset: 0

Views

Author

Paul Boddington, Jun 04 2004

Keywords

Comments

See A090751 for definition of indecomposable.

Crossrefs

Cf. A000679.

Formula

Inverse Euler transform of A000679. - Franklin T. Adams-Watters, Sep 22 2006

Extensions

More terms from Franklin T. Adams-Watters, Sep 22 2006
a(0) changed to 0 by Eric M. Schmidt, Jun 07 2014

A109230 Number of indecomposable groups with n conjugacy classes.

Original entry on oeis.org

0, 1, 2, 3, 8, 6, 12, 14
Offset: 1

Views

Author

Paul Boddington, Aug 19 2005

Keywords

Comments

See A090751 for the definition of indecomposable. The comments there imply that A073043 has Dirichlet generating function prod((1-n^(-s))^(-a(n)),n>=2).

A122697 Number of indecomposable partitions of n.

Original entry on oeis.org

0, 2, 3, 2, 7, 5, 15, 14, 24, 28, 56, 52, 101, 105, 155, 189, 297, 310, 490, 536, 747, 890, 1255, 1380, 1930, 2234, 2928, 3433, 4565, 5133, 6842, 7881, 9975, 11716, 14778, 17006, 21637, 25035, 30882, 35972, 44583, 51200, 63261, 73115, 88459, 103048
Offset: 1

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Author

Keywords

Comments

A partition is indecomposable if it is not [1] and cannot be represented as the product of two smaller partitions, where the product of two partitions is the multiset of all products of parts from the two multiplicands. Another way to define the product of partitions is to regard the partition as a finite sequence b(k) being the number of parts of size k; then the Dirichlet g.f. of b * c is the product of the Dirichlet g.f.s of b and c.

Examples

			The product of [2,2,1] * [2,1,1] is the partition with parts:
4 4 2
2 2 1
2 2 1
which is [4^2,2^5,1^2]. In terms of Dirichlet g.f.s, this is (2*2^s + 1^s) * (2^s + 2*1^s) = (2*4^s + 5*2^s + 2*1^s).
Of the partitions of 6, [6] = [3] * [2], [4,2] = [2] * [2,1], [3^2] = [3] * [1^2], [2^3] = [2] * [1^3], [2^2,1^2] = [2,1] * [1^2] and [1^6] = [1^3] * [1^2]. This leaves [5,1], [4,1^2], [3,2,1], [3,1^3] and [2,1^4] as the 5 indecomposable partitions of 6.
		

Crossrefs

Formula

The (formal) Dirichlet generating function for A000041 is Product_{n>1} 1/(1-n^{-s})^a(n). (Formal because this g.f. does not converge for any value of s.)

A243592 Numbers n such that there is no indecomposable group of order n.

Original entry on oeis.org

1, 15, 33, 35, 45, 51, 65, 69, 77, 85, 87, 91, 95, 99, 105, 115, 119, 123, 133, 135, 141, 143, 145, 153, 159, 161, 165, 175, 177, 185, 187, 195, 207, 209, 213, 215, 217, 221, 231, 235, 245, 247, 249, 255, 259, 261, 265, 267, 285, 287, 295, 297, 299, 303, 315, 319, 321, 323, 325, 329, 335, 339, 341, 345, 357, 365, 369, 371
Offset: 1

Views

Author

Joerg Arndt, Jun 07 2014

Keywords

Comments

Numbers n such that A090751(n) = 0.
Includes all non-prime-power members of A051532. - Eric M. Schmidt, Jun 07 2014
Showing 1-7 of 7 results.