A107680 Repeating k-th ternary repunit (A003462) 2^k times, k >= 0.
0, 1, 1, 4, 4, 4, 4, 13, 13, 13, 13, 13, 13, 13, 13, 40, 40, 40, 40, 40, 40, 40, 40, 40, 40, 40, 40, 40, 40, 40, 40, 121, 121, 121, 121, 121, 121, 121, 121, 121, 121, 121, 121, 121, 121, 121, 121, 121, 121, 121, 121, 121, 121, 121, 121, 121, 121, 121, 121, 121, 121, 121
Offset: 0
Keywords
Examples
k=1: A003462(1) = (3^1-1)/2 = 1, therefore a(1) = a(2^1) = 1; k=2: A003462(2) = (3^2-1)/2 = 4, therefore a(2+1) = a(2+2) = a(2+3) = a(2+2^2) = 4.
Crossrefs
Programs
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Mathematica
With[{nn=5},Flatten[Table[#[[1]],{#[[2]]}]&/@Thread[{Table[FromDigits[ PadRight[{},n,1],3],{n,nn}],2^Range[nn]}]]] (* Harvey P. Dale, Jan 04 2013 *)
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PARI
apply( {A107680(n)=3^exponent(n+1)\2}, [0..66]) \\ M. F. Hasler, Jun 22 2020
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Python
def A107680(n): return 3**((n+1).bit_length()-1)-1>>1 # Chai Wah Wu, Nov 07 2024
Formula
Extensions
Corrected by T. D. Noe, Oct 25 2006
Extended to a(0) = 0 by M. F. Hasler, Jun 23 2020
Comments