cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

Showing 1-5 of 5 results.

A107788 Numbers of the form (8^i)*(11^j), with i, j >= 0.

Original entry on oeis.org

1, 8, 11, 64, 88, 121, 512, 704, 968, 1331, 4096, 5632, 7744, 10648, 14641, 32768, 45056, 61952, 85184, 117128, 161051, 262144, 360448, 495616, 681472, 937024, 1288408, 1771561, 2097152, 2883584, 3964928, 5451776, 7496192, 10307264
Offset: 1

Views

Author

Douglas Winston (douglas.winston(AT)srupc.com), Jun 14 2005

Keywords

Crossrefs

Programs

  • Haskell
    import Data.Set (singleton, deleteFindMin, insert)
    a107788 n = a107788_list !! (n-1)
    a107788_list = f $ singleton (1,0,0) where
       f s = y : f (insert (8 * y, i + 1, j) $ insert (11 * y, i, j + 1) s')
             where ((y, i, j), s') = deleteFindMin s
    -- Reinhard Zumkeller, May 15 2015
  • Mathematica
    Take[Union[8^First[#]*11^Last[#]&/@Tuples[Range[0,20],2]],40] (* Harvey P. Dale, Jan 17 2015 *)
    n = 10^6; Flatten[Table[8^i*11^j, {i, 0, Log[8, n]}, {j, 0, Log[11, n/8^i]}]] // Sort (* Amiram Eldar, Oct 07 2020 *)

Formula

Sum_{n>=1} 1/a(n) = (8*11)/((8-1)*(11-1)) = 44/35. - Amiram Eldar, Oct 07 2020
a(n) ~ exp(sqrt(2*log(8)*log(11)*n)) / sqrt(88). - Vaclav Kotesovec, Oct 07 2020

A108687 Numbers of the form (9^i)*(11^j), with i, j >= 0.

Original entry on oeis.org

1, 9, 11, 81, 99, 121, 729, 891, 1089, 1331, 6561, 8019, 9801, 11979, 14641, 59049, 72171, 88209, 107811, 131769, 161051, 531441, 649539, 793881, 970299, 1185921, 1449459, 1771561, 4782969, 5845851, 7144929, 8732691, 10673289, 13045131
Offset: 1

Views

Author

Douglas Winston (douglas.winston(AT)srupc.com), Jun 17 2005

Keywords

Crossrefs

Programs

  • Haskell
    import Data.Set (singleton, deleteFindMin, insert)
    a108687 n = a108687_list !! (n-1)
    a108687_list = f $ singleton (1,0,0) where
       f s = y : f (insert (9 * y, i + 1, j) $ insert (11 * y, i, j + 1) s')
             where ((y, i, j), s') = deleteFindMin s
    -- Reinhard Zumkeller, May 15 2015
    
  • Mathematica
    f[upto_]:=With[{max9=Floor[Log[9,upto]],max11=Floor[Log[11,upto]]}, Select[Union[Times@@{9^First[#],11^Last[#]}&/@Tuples[{Range[0, max9], Range[0, max11]}]], #<=upto&]]; f[14000000]  (* Harvey P. Dale, Mar 11 2011 *)
  • Python
    from sympy import integer_log
    def A108687(n):
        def bisection(f,kmin=0,kmax=1):
            while f(kmax) > kmax: kmax <<= 1
            kmin = kmax >> 1
            while kmax-kmin > 1:
                kmid = kmax+kmin>>1
                if f(kmid) <= kmid:
                    kmax = kmid
                else:
                    kmin = kmid
            return kmax
        def f(x): return n+x-sum(integer_log(x//11**i,9)[0]+1 for i in range(integer_log(x,11)[0]+1))
        return bisection(f,n,n) # Chai Wah Wu, Mar 25 2025

Formula

Sum_{n>=1} 1/a(n) = (9*11)/((9-1)*(11-1)) = 99/80. - Amiram Eldar, Sep 24 2020
a(n) ~ exp(sqrt(2*log(9)*log(11)*n)) / sqrt(99). - Vaclav Kotesovec, Sep 24 2020

A108761 Numbers of the form (10^i)*(13^j), with i, j >= 0.

Original entry on oeis.org

1, 10, 13, 100, 130, 169, 1000, 1300, 1690, 2197, 10000, 13000, 16900, 21970, 28561, 100000, 130000, 169000, 219700, 285610, 371293, 1000000, 1300000, 1690000, 2197000, 2856100, 3712930, 4826809, 10000000, 13000000, 16900000
Offset: 1

Views

Author

Douglas Winston (douglas.winston(AT)srupc.com), Jun 24 2005

Keywords

Crossrefs

Programs

  • Haskell
    import Data.Set (singleton, deleteFindMin, insert)
    a108761 n = a108761_list !! (n-1)
    a108761_list = f $ singleton (1,0,0) where
       f s = y : f (insert (10 * y, i + 1, j) $ insert (13 * y, i, j + 1) s')
             where ((y, i, j), s') = deleteFindMin s
    -- Reinhard Zumkeller, May 15 2015
  • Mathematica
    n = 10^7; Flatten[Table[10^i*13^j, {i, 0, Log10[n]}, {j, 0, Log[13, n/10^i]}]] // Sort (* Amiram Eldar, Sep 25 2020 *)

Formula

Sum_{n>=1} 1/a(n) = (10*13)/((10-1)*(13-1)) = 65/54. - Amiram Eldar, Sep 25 2020
a(n) ~ exp(sqrt(2*log(10)*log(13)*n)) / sqrt(130). - Vaclav Kotesovec, Sep 25 2020

A108748 Numbers of the form (9^i)*(13^j), with i, j >= 0.

Original entry on oeis.org

1, 9, 13, 81, 117, 169, 729, 1053, 1521, 2197, 6561, 9477, 13689, 19773, 28561, 59049, 85293, 123201, 177957, 257049, 371293, 531441, 767637, 1108809, 1601613, 2313441, 3341637, 4782969, 4826809, 6908733, 9979281, 14414517, 20820969
Offset: 1

Views

Author

Douglas Winston (douglas.winston(AT)srupc.com), Jun 23 2005

Keywords

Crossrefs

Programs

  • Mathematica
    n = 10^6; Flatten[Table[9^i*13^j, {i, 0, Log[9, n]}, {j, 0, Log[13, n/9^i]}]] // Sort (* Amiram Eldar, Sep 25 2020 *)

Formula

Sum_{n>=1} 1/a(n) = (9*13)/((9-1)*(13-1)) = 39/32. - Amiram Eldar, Sep 25 2020
a(n) ~ exp(sqrt(2*log(9)*log(13)*n)) / sqrt(117). - Vaclav Kotesovec, Sep 25 2020

A108771 Numbers of the form (12^i)*(13^j), with i, j >= 0.

Original entry on oeis.org

1, 12, 13, 144, 156, 169, 1728, 1872, 2028, 2197, 20736, 22464, 24336, 26364, 28561, 248832, 269568, 292032, 316368, 342732, 371293, 2985984, 3234816, 3504384, 3796416, 4112784, 4455516, 4826809, 35831808, 38817792, 42052608, 45556992
Offset: 1

Views

Author

Douglas Winston (douglas.winston(AT)srupc.com), Jun 25 2005

Keywords

Crossrefs

Programs

  • Maple
    N:= 10^8: # to get all terms <= N
    sort([seq(seq(12^i*13^j, j = 0 .. floor(log[13](N/12^i))), i=0..floor(log[12](N)))]); # Robert Israel, Jun 16 2019
  • Mathematica
    With[{max = 5*10^7}, Flatten[Table[12^i*13^j, {i, 0, Log[12, max]}, {j, 0, Log[13, max/12^i]}]] // Sort] (* Amiram Eldar, Mar 29 2025 *)

Formula

Sum_{n>=1} 1/a(n) = 13/11. - Amiram Eldar, Mar 29 2025
Showing 1-5 of 5 results.