cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

A128223 a(n) = if n mod 2 = 0 then n*(n+1)/2 otherwise (n+1)^2/2-1.

Original entry on oeis.org

0, 1, 3, 7, 10, 17, 21, 31, 36, 49, 55, 71, 78, 97, 105, 127, 136, 161, 171, 199, 210, 241, 253, 287, 300, 337, 351, 391, 406, 449, 465, 511, 528, 577, 595, 647, 666, 721, 741, 799, 820, 881, 903, 967, 990, 1057, 1081, 1151, 1176, 1249, 1275, 1351, 1378, 1457, 1485
Offset: 0

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Author

Gary W. Adamson, Feb 19 2007

Keywords

Comments

a(n-1) is the length of the shortest path along the edges of the complete graph with n vertices. - Martin Fuller, Dec 06 2007
From Peter Kagey, Jan 25 2015: (Start)
For an irreflexive, non-transitive, symmetric relation, a(n) is the length of a relation chain required to demonstrate that a != b for all distinct elements a and b in S, where S contains n+1 elements.
For example, for the set {1,2,3} the chain requires a(2) = 3 relations (e.g., 1 != 2 != 3 != 1). For the set {1,2,3,4}, the chain requires a(3) = 7 relations (e.g., 1 != 2 != 3 != 4 != 1 != 3 != 2 != 4 -- noting the redundancy of 2!=3 and 3!=2). (End)
Given a set of n lots of n distinct items, it is possible to sort the items from fully collated (ABCABCABC) to fully sorted (AAABBBCCC), or vice versa, using a sorting algorithm whereby at each step a portion of the overall string is selected and its contents reversed. The minimum number of steps such an algorithm will take is a(n-1). For example, when n=3, a(n-1)=3: ABCABCABC -> ABBACBACC -> ABBAABCCC -> AAABBBCCC. - Elliott Line, Aug 02 2019

Examples

			a(5) = 17 = (5 + 1 + 5 + 1 + 5), row 5 of A128222.
		

Crossrefs

Row sums of A128222.
Cf. A024206, row sums of A128221 = A128174 * A127701.

Programs

  • Haskell
    a128223 n = if even n then n*(n + 1) `div` 2 else (n+1)^2 `div` 2 - 1 -- Peter Kagey, Jul 14 2015
    
  • Magma
    [(-1+(-1)^n-(-3+(-1)^n)*n+2*n^2)/4: n in [0..60]]; // Vincenzo Librandi, Mar 18 2015
    
  • Maple
    f:=n-> if n mod 2 = 0 then n*(n+1)/2 else (n+1)^2/2-1; fi;
  • Mathematica
    f[n_] := If[EvenQ@ n, n (n + 1)/2, (n + 1)^2/2 - 1]; Array[f, 54] (* Michael De Vlieger, Mar 17 2015 *)
    Table[(- 1 + (-1)^n - (- 3 + (-1)^n) n + 2 n^2) / 4, {n, 0, 60}] (* Vincenzo Librandi, Mar 18 2015 *)
    CoefficientList[ Series[(-x - 2x^2 - 2x^3 + x^4)/((-1 + x)^3 (1 + x)^2), {x, 0, 54}], x] (* Robert G. Wilson v, Nov 16 2016 *)
    LinearRecurrence[{1,2,-2,-1,1},{0,1,3,7,10},60] (* Harvey P. Dale, Mar 17 2020 *)
  • PARI
    main(size)={my(n,m,v=vector(size),i);for(i=0,size-1,v[i+1]=if(i%2==0,i*(i+1)/2,(i+1)^2/2-1));return(v);} /* Anders Hellström, Jul 14 2015 */

Formula

a(n) = (-1+(-1)^n-(-3+(-1)^n)*n+2*n^2)/4. a(n) = a(n-1)+2*a(n-2)-2*a(n-3)-a(n-4)+a(n-5). G.f.: x*(x^3-2*x^2-2*x-1) / ((x-1)^3*(x+1)^2). - Colin Barker, Oct 16 2013
a(n) = A053439(n) - 1. - Peter Kagey, Nov 16 2016

Extensions

Edited by N. J. A. Sloane, Dec 06 2007