A136760 a(n) = leading digit of n! in base 9.
1, 1, 2, 6, 2, 1, 8, 6, 6, 6, 6, 8, 1, 1, 2, 4, 8, 1, 3, 7, 1, 4, 1, 2, 7, 2, 6, 2, 7, 2, 8, 3, 1, 4, 1, 7, 3, 1, 6, 3, 1, 7, 3, 1, 1, 5, 3, 1, 1, 5, 3, 2, 1, 8, 5, 3, 2, 1, 1, 8, 6, 4, 3, 2, 2, 1, 1, 1, 1, 7, 6, 6, 5, 4, 4, 4, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 4, 4, 4, 5, 5, 6, 7, 8, 1, 1, 1, 1, 2, 2
Offset: 0
Examples
a(10) = 6 as 10! = 6740700_9 which has leading digit 6. - _David A. Corneth_, Jan 15 2021
Links
- David A. Corneth, Table of n, a(n) for n = 0..9999
Crossrefs
Programs
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Mathematica
f[n_]:=First[IntegerDigits[n!,9]]; lst={};Do[AppendTo[lst,f[n]],{n,0,2*5!}];lst (* Vladimir Joseph Stephan Orlovsky, Jun 14 2009 *) IntegerDigits[#,9][[1]]&/@(Range[0,100]!) (* Harvey P. Dale, Jun 21 2021 *)
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PARI
a(n) = digits(n!, 9)[1]; \\ Michel Marcus, Jan 27 2015