A145609 Numerator of the polynomial A_l(x) = sum_{d=1..l-1} x^(l-d)/d for index l=2n+1 evaluated at x=1.
3, 25, 49, 761, 7381, 86021, 1171733, 2436559, 14274301, 55835135, 19093197, 1347822955, 34395742267, 315404588903, 9304682830147, 586061125622639, 54062195834749, 54801925434709, 2053580969474233, 2078178381193813
Offset: 1
Links
- Vincenzo Librandi, Table of n, a(n) for n = 1..200
Programs
-
Maple
A := proc(l,x) add(x^(l-d)/d,d=1..l-1) ; end: A145609 := proc(n) numer( A(2*n+1,1)) ; end: seq(A145609(n),n=1..20) ; # R. J. Mathar, Aug 21 2009
-
Mathematica
m = 1; aa = {}; Do[k = 0; Do[k = k + m^(2 r + 1 - d)/d, {d, 1, 2 r}]; AppendTo[aa, Numerator[k]], {r, 1, 25}]; aa (* Artur Jasinski *)
Formula
(1/(2*n+1))*2F1(1, 2*n+1; 2*n+2; 1/m) = Sum_{x>=0} m^(-x)/(x+2n+1) = m^(2n)*arctanh((2m-1)/(2m^2-2m+1)) - A_{2n+1}(m) = m^(2n)*log(m/(m-1)) - A_{2n+1}(m). - Artur Jasinski, Oct 14 2008
It appears that A145609(n)/A145610(n) = H(2*n+2), the harmonic number of order 2*n+2. - Groux Roland, Jan 08 2011
Yes, A145609(n)/A145610(n) = H(2*n+2), as A_l(x) = sum_{d=1..l-1} x^(l-d)/d at x=1 is just sum_{d=1..l-1}1/d = H(l-1), the harmonic number of order (l-1). - Zak Seidov, Jan 09 2014
a(n) = numerator of Integral_{x=0..1} (1 - x^(2*n))/(1 - x). - Peter Luschny, Sep 28 2017
Extensions
Edited, parentheses in front of Gauss. Hypg. Fct. added by R. J. Mathar, Aug 21 2009
Comments