A146162 Expansion of eta(q^2)^2 * eta(q^5) / (eta(q) * eta(q^4)^2) in powers of q.
1, 1, 0, 1, 2, 1, 0, 2, 4, 3, 0, 3, 8, 4, 0, 6, 14, 8, 0, 10, 22, 12, 0, 16, 36, 21, 0, 25, 56, 30, 0, 38, 84, 48, 0, 57, 126, 68, 0, 84, 184, 102, 0, 121, 264, 143, 0, 172, 376, 207, 0, 243, 528, 284, 0, 338, 732, 400, 0, 465, 1008, 542, 0, 636, 1374, 744, 0, 862, 1856, 996, 0
Offset: 0
Keywords
Examples
1 + q + q^3 + 2*q^4 + q^5 + 2*q^7 + 4*q^8 + 3*q^9 + 3*q^11 + 8*q^12 + ...
Links
- G. C. Greubel, Table of n, a(n) for n = 0..1000
Programs
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Mathematica
a[n_]:= SeriesCoefficient[QPochhammer[x^5]/(QPochhammer[x]* QPochhammer[ -x^2, x^2]^2), {x, 0, n}]; Table[a[n], {n, 0, 50}] (* G. C. Greubel, Dec 04 2017 *)
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PARI
{a(n) = local(A); if( n<0, 0, A = x * O(x^n); polcoeff( eta(x^2 + A)^2 * eta(x^5 + A) / (eta(x + A) * eta(x^4 + A)^2), n))}
Formula
Euler transform of period 20 sequence [ 1, -1, 1, 1, 0, -1, 1, 1, 1, -2, 1, 1, 1, -1, 0, 1, 1, -1, 1, 0, ...].
G.f. is a period 1 Fourier series which satisfies f(-1 / (80 t)) = (4/5)^(1/2) g(t) where q = exp(2 Pi i t) and g() is g.f. for A146164.
a(4*n + 2) = 0.