cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

A152525 a(n) is the number of unordered pairs of disjoint set partitions of an n-element set.

Original entry on oeis.org

0, 0, 1, 7, 65, 811, 12762, 244588, 5574956, 148332645, 4538695461, 157768581675, 6167103354744, 268758895112072, 12961171404183498, 687270616305277589, 39843719438374998543, 2512873126513271758171, 171643113190082528007702, 12647168303374365311984284
Offset: 0

Views

Author

David Pasino, Dec 06 2008, Dec 08 2008

Keywords

Examples

			From _Gus Wiseman_, Dec 09 2018: (Start)
The a(3) = 7 unordered pairs:
  {{1},{2},{3}}| {{1,2,3}}
   {{1},{2,3}} |{{1,2},{3}}
   {{1},{2,3}} |{{1,3},{2}}
   {{1,2},{3}} |{{1,3},{2}}
   {{1},{2,3}} | {{1,2,3}}
   {{1,2},{3}} | {{1,2,3}}
   {{1,3},{2}} | {{1,2,3}}
(End)
		

Crossrefs

Programs

  • Maple
    a:= n-> add(binomial(n,k)*binomial(combinat[bell](k),2)*
            add(Stirling2(n-k,j)*(-1)^j, j=0..n-k), k=0..n):
    seq(a(n), n=0..20);  # Alois P. Heinz, May 27 2018
  • Mathematica
    Array[Sum[Binomial[#, k] Sum[(-1)^j*StirlingS2[# - k, j], {j, 0, # - k}] Binomial[BellB@ k, 2], {k, 0, #}] &, 20, 0] (* Michael De Vlieger, May 27 2018 *)
  • PARI
    a000110(n) = polcoeff( sum( k=0, n, prod( i=1, k, x / (1 - i*x)), x^n * O(x)), n);
    a(n) = sum(k=0, n, binomial(n,k) * sum(j=0, n-k, (-1)^j*stirling(n-k,j, 2) * binomial(a000110(k),2))); \\ Michel Marcus, May 27 2018

Formula

a(n) = Sum_{k=0..n} binomial(n,k) * (Sum_{j=0..n-k} (-1)^j*A048993(n-k,j)) * binomial(A000110(k),2).
That is, summed on k from 0 to n, the number of k-element subsets of an n-element set, times the alternating sum of row n-k of Stirling2 numbers starting with +S(n-k, 0), times the number of pairs of partitions of k elements.
Obtained by inverting (binomial(A000110(n), 2)) = (Sum_{k=0..n} binomial(n,k)*A000110(n-k)*a(k)), which in turn is gotten by considering that a pair of conjoint partitions is gotten by choosing a partition of a subset and then choosing a pair of disjoint partitions of the complement.