cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

Showing 1-2 of 2 results.

A244003 A(n,k) = k^Fibonacci(n); square array A(n,k), n>=0, k>=0, read by antidiagonals.

Original entry on oeis.org

1, 1, 0, 1, 1, 0, 1, 2, 1, 0, 1, 3, 2, 1, 0, 1, 4, 3, 4, 1, 0, 1, 5, 4, 9, 8, 1, 0, 1, 6, 5, 16, 27, 32, 1, 0, 1, 7, 6, 25, 64, 243, 256, 1, 0, 1, 8, 7, 36, 125, 1024, 6561, 8192, 1, 0, 1, 9, 8, 49, 216, 3125, 65536, 1594323, 2097152, 1, 0
Offset: 0

Views

Author

Alois P. Heinz, Jun 17 2014

Keywords

Examples

			Square array A(n,k) begins:
  1, 1,   1,    1,     1,      1,       1, ...
  0, 1,   2,    3,     4,      5,       6, ...
  0, 1,   2,    3,     4,      5,       6, ...
  0, 1,   4,    9,    16,     25,      36, ...
  0, 1,   8,   27,    64,    125,     216, ...
  0, 1,  32,  243,  1024,   3125,    7776, ...
  0, 1, 256, 6561, 65536, 390625, 1679616, ...
		

Crossrefs

Rows n=0, 1+2, 3-8 give: A000012, A001477, A000290, A000578, A000584, A001016, A010801, A010809.
Main diagonal gives: A152915.

Programs

  • Maple
    A:= (n, k)-> k^(<<1|1>, <1|0>>^n)[1, 2]:
    seq(seq(A(n, d-n), n=0..d), d=0..12);
  • Mathematica
    A[0, 0] = 1; A[n_, k_] := k^Fibonacci[n]; Table[A[n-k, k], {n, 0, 12}, {k, n, 0, -1}] // Flatten (* Jean-François Alcover, Nov 11 2015 *)

Formula

A(n,k) = k^A000045(n).
A(0,k) = 1, A(1,k) = k, A(n,k) = A(n-1,k) * A(n-2,k) for n>=2.

A100399 a(n) = Fibonacci(n)^n.

Original entry on oeis.org

1, 1, 1, 8, 81, 3125, 262144, 62748517, 37822859361, 60716992766464, 253295162119140625, 2775173073766990340489, 79496847203390844133441536, 5965226978431093156430190442313, 1171598758708107367475386427203165009, 602486784535040403801858901000000000000000
Offset: 0

Views

Author

Jorge Coveiro, Dec 30 2004

Keywords

Crossrefs

Main diagonal of A103323.

Programs

Formula

a(n) = A103323(n,n).
From Amiram Eldar, Nov 17 2020: (Start)
Sum_{n>=1} 1/a(n) = A201615.
Sum_{n>=1} (-1)^(n+1)/a(n) = A201616. (End)
Showing 1-2 of 2 results.