A157641 Triangle of the elementwise product of binomial coefficients with q-binomial coefficients [n,k] for q = 4.
1, 1, 1, 1, 10, 1, 1, 63, 63, 1, 1, 340, 2142, 340, 1, 1, 1705, 57970, 57970, 1705, 1, 1, 8190, 1396395, 7536100, 1396395, 8190, 1, 1, 38227, 31307913, 847301455, 847301455, 31307913, 38227, 1, 1, 174760, 668055052, 86847156760, 435512947870
Offset: 0
Examples
Triangle begins: 1; 1, 1; 1, 10, 1; 1, 63, 63, 1; 1, 340, 2142, 340, 1; 1, 1705, 57970, 57970, 1705, 1; 1, 8190, 1396395, 7536100, 1396395, 8190, 1; 1, 38227, 31307913, 847301455, 847301455, 31307913, 38227, 1; ...
Links
- Andrew Howroyd, Table of n, a(n) for n = 0..1274
Programs
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Magma
q:=4; [[k le 0 select 1 else Binomial(n,k)*(&*[(1-q^(n-j))/(1-q^(j+1)): j in [0..(k-1)]]): k in [0..n]]: n in [0..10]]; // G. C. Greubel, Nov 17 2018
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Mathematica
t[n_, m_] = Product[Sum[k*(m + 1)^i, {i, 0, k - 1}], {k, 1, n}]; b[n_, k_, m_] = t[n, m]/(t[k, m]*t[n - k, m]); Flatten[Table[Table[b[n, k, 3], {k, 0, n}], {n, 0, 10}]]
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PARI
T(n, k) = {binomial(n, k)*polcoef(x^k/prod(j=0, k, 1-4^j*x+x*O(x^n)), n)} \\ Andrew Howroyd, Nov 19 2018
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PARI
my(q=4); for(n=0,10, for(k=0,n, print1(binomial(n,k)*prod(j=0,k-1, (1-q^(n-j))/(1-q^(j+1))), ", "));print) \\ G. C. Greubel, Nov 17 2018
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Sage
[[ binomial(n,k)*gaussian_binomial(n,k).subs(q=4) for k in range(n+1)] for n in range(10)] # G. C. Greubel, Nov 17 2018
Formula
T(n,k) = t(n)/(t(k)*t(n-k)) where t(n) = Product_{k=1..n} Sum_{i=0..k-1} k*4^i.
T(n,k) = binomial(n,k) * A022168(n,k) for 0 <= k <= n. - Werner Schulte, Nov 16 2018
Extensions
Edited and simpler name by Werner Schulte and Andrew Howroyd, Nov 19 2018
Comments