A160592 -id:A160592 - cp's OEIS frontend

A116615 Values of n such that prime(2n) mod 12 = 7.

2, 4, 7, 11, 17, 18, 19, 23, 24, 29, 45, 57, 69, 94, 101, 105, 111, 112, 116, 121, 129, 133, 136, 137, 138, 141, 150, 157, 162, 164, 170, 172, 174, 177, 184, 187, 197, 203, 207, 209, 220, 231, 235, 239, 245, 250, 251, 252, 254, 255, 260, 261, 270, 273, 276, 283

Offset: 1

Roger L. Bagula, Mar 29 2006

nonn

			23 is in the sequence because the 46th prime is 199 and 199 mod 12=7.

G. C. Greubel, Table of n, a(n) for n = 1..1000

Cf. A116602, A116610, A116612-A116617, A160591-A160594. [M. F. Hasler, May 22 2009]

a:=proc(n) if ithprime(2*n) mod 12 = 7 then n else fi end: seq(a(n),n=1..300);

Select[Range[1, 500], Mod[Prime[2*#], 12] == 7 &] (* G. C. Greubel, Nov 19 2017 *)

for( n=1,999, prime(2*n)%12==7 & print1(n",")) \\ M. F. Hasler, May 22 2009

Equals (1/2) * { even terms in A160592 = A000720(A068229) }. - M. F. Hasler, May 22 2009

Edited by N. J. A. Sloane, Apr 05 2006

A116616 Values of n such that prime(2n+1) mod 12 = 7.

Original entry on oeis.org

5, 9, 13, 15, 23, 30, 31, 33, 36, 37, 42, 46, 47, 49, 50, 52, 55, 57, 58, 62, 64, 65, 66, 70, 71, 74, 76, 77, 78, 81, 83, 87, 88, 89, 90, 96, 103, 106, 108, 114, 116, 117, 121, 123, 124, 130, 134, 142, 144, 148, 151, 152, 160, 163, 166, 167, 175, 182, 185, 191, 192

Offset: 1

Roger L. Bagula, Mar 29 2006

nonn

			33 is in the sequence because the 67th prime is 331 and 331 mod 12=7.

G. C. Greubel, Table of n, a(n) for n = 1..1000

Cf. A116602, A116610, A116612-A116617, A160591-A160594. [M. F. Hasler, May 22 2009]

a:=proc(n) if ithprime(2*n+1) mod 12 = 7 then n else fi end: seq(a(n),n=0..215);

Select[Range[220], Mod[Prime[2# + 1], 12] == 7 &] (* Stefan Steinerberger, Apr 08 2006 *)

for(n=1,999, prime(2*n+1)%12==7 & print1(n",")) \\ M. F. Hasler, May 22 2009

Equals { odd terms in A160592 = A000720(A068229) } / 2, rounded towards zero. - M. F. Hasler, May 22 2009

Edited by N. J. A. Sloane, Apr 05 2006

cp's OEIS Frontend

A116615 Values of n such that prime(2n) mod 12 = 7.

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