A164882 Numbers n such that sum of the cubes of the digits of n^3 is a perfect cube.

0, 1, 2, 10, 20, 78, 100, 118, 200, 237, 303, 501, 780, 1000, 1005, 1039, 1079, 1145, 1180, 1562, 2000, 2224, 2370, 3003, 3030, 3304, 4105, 4339, 5001, 5010, 5235, 5478, 5705, 5829, 6096, 6459, 6475, 6493, 6795, 7154, 7221, 7444, 7800, 8494, 9168, 9462

Offset: 1

Author

Gaurav Kumar, Aug 29 2009

Keywords

• nonn
• base

Examples

			a(6) = 78 since 78^3 = 474552 and 4^3 + 7^3 + 4^3 + 5^3 + 5^3 + 2^3 = 729 = 9^3
		

Links

• Zak Seidov, Table of n, a(n) for n = 1..1741 (all terms up to 10^6).

Programs

Mathematica

Select[Range[0,10000],IntegerQ[Power[Total[IntegerDigits[#^3]^3], (3)^-1]]&] (* Harvey P. Dale, Mar 17 2012 *)

Extensions

Typo in name fixed by Zak Seidov, May 21 2013