A174091 a(n) = n OR 2.
2, 3, 2, 3, 6, 7, 6, 7, 10, 11, 10, 11, 14, 15, 14, 15, 18, 19, 18, 19, 22, 23, 22, 23, 26, 27, 26, 27, 30, 31, 30, 31, 34, 35, 34, 35, 38, 39, 38, 39, 42, 43, 42, 43, 46, 47, 46, 47, 50, 51, 50, 51, 54, 55, 54, 55, 58, 59, 58, 59, 62, 63, 62, 63, 66, 67, 66
Offset: 0
Examples
a(3) = 3 because OR(0011, 0010) = 0011 = 3. a(4) = 6 because OR(0100, 0010) = 0110 = 6. a(5) = 7 because OR(0101, 0010) = 0111 = 7.
Links
- Shane Chern, T. Cai, and H. Zhong, On the cardinality and sum of reciprocals of primitive sequences, Preprint 2018; To appear in Adv. Math. (China).
- Index entries for linear recurrences with constant coefficients, signature (2,-2,2,-1).
Programs
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Maple
with(Bits): seq(Or(n,2), n=0..60);
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Mathematica
Table[BitOr[n, 2], {n, 0, 100}] (* Alonso del Arte, Feb 06 2013 *) LinearRecurrence[{2,-2,2,-1},{2,3,2,3},80] (* Harvey P. Dale, Oct 25 2016 *)
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PARI
a(n)=bitor(n,2) \\ Charles R Greathouse IV, Feb 27 2013
Formula
a(n) = n + 1 + (-1)^floor(n/2).
G.f.: ( 2-x+x^3 ) / ( (1+x^2)*(x-1)^2 ). - R. J. Mathar, Feb 27 2013
Sum_{n>=0} (-1)^n/a(n) = Pi/4 - log(2)/2 = A196521. - Peter McNair, Aug 05 2023
Comments