A178186 Sum 3^((k^2+3k)/2) from k=1 to n.
9, 252, 19935, 4802904, 3491587305, 7629089072292, 50039174188071999, 984820941357799304880, 58150721823981417489695049, 10301109611599361435391036962892, 5474411390529830981438591324606714655
Offset: 1
Keywords
Links
- Vincenzo Librandi, Table of n, a(n) for n = 1..60
Programs
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Mathematica
aa = {}; m = 3; sum = 0; Do[sum = sum + m^((n + 3) n/2); AppendTo[aa, sum], {n, 1, 20}]; aa (*Artur Jasinski*) Table[Sum[3^((k^2+3k)/2),{k,n}],{n,20}] (* Harvey P. Dale, Jul 10 2020 *) Accumulate[Table[3^((k^2+3k)/2),{k,15}]] (* Harvey P. Dale, Mar 25 2023 *)
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PARI
a(n) = sum(k=1, n, 3^((k^2+3*k)/2)); \\ Michel Marcus, Sep 09 2013
Comments