A178784 Let d be the vector of divisors of 100 sorted from largest to smallest, i.e., [100,50,25,20,10,5,4,2,1]. Then a(n) = 100/d(n) - 1.
0, 1, 3, 4, 9, 19, 24, 49, 99
Offset: 1
Crossrefs
Cf. A018283.
Programs
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Mathematica
Map[(100/# - 1)&, Sort[Divisors[100], Greater]] Map[(#-1)&,Divisors[100]] (* Ross La Haye, Jun 17 2010 *) 100/Reverse[Divisors[100]]-1 (* Harvey P. Dale, Jan 14 2015 *)
Formula
a(n) = 100/A018283(10-n) - 1.
a(n) = A018283(n) - 1. - Ross La Haye, Jun 17 2010