A179477 Antonym of A014824: each term is 10 times the previous term minus n.
10, 99, 988, 9877, 98766, 987655, 9876544, 98765433, 987654322, 9876543211, 98765432100, 987654320989, 9876543209878, 98765432098767, 987654320987656, 9876543209876545, 98765432098765434, 987654320987654323, 9876543209876543212, 98765432098765432101
Offset: 0
Links
- Colin Barker, Table of n, a(n) for n = 0..998
- Index entries for linear recurrences with constant coefficients, signature (12,-21,10).
Crossrefs
Cf. A014824.
Programs
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Mathematica
Join[{a=10,b=99},Table[c=11*b-10*a-1;a=b;b=c,{n,60}]] (* Vladimir Joseph Stephan Orlovsky, Jan 20 2011*) Join[{a=10}, Table[a=10a-n, {n,60}]] (* T. D. Noe, Jan 20 2011 *)
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PARI
Vec(-(10*x^2-21*x+10)/((x-1)^2*(10*x-1)) + O(x^30)) \\ Colin Barker, Oct 03 2015
Formula
a(n) + A014824(n) = 10^(n+1).
From Colin Barker, Oct 03 2015: (Start)
a(n) = 12*a(n-1) - 21*a(n-2) + 10*a(n-3) for n>2.
G.f.: -(10*x^2-21*x+10) / ((x-1)^2*(10*x-1)). (End)
a(n) = (10 + 2^(5+n)*5^(2+n) + 9*n)/81. - Colin Barker, Mar 25 2017