cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

Showing 1-2 of 2 results.

A191967 n * (numbers that are not divisible by 3).

Original entry on oeis.org

0, 1, 4, 12, 20, 35, 48, 70, 88, 117, 140, 176, 204, 247, 280, 330, 368, 425, 468, 532, 580, 651, 704, 782, 840, 925, 988, 1080, 1148, 1247, 1320, 1426, 1504, 1617, 1700, 1820, 1908, 2035, 2128, 2262, 2360, 2501, 2604, 2752, 2860, 3015, 3128, 3290, 3408
Offset: 0

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Author

Reinhard Zumkeller, Jul 07 2012

Keywords

Comments

A033579 and A033570 interleaved.

Crossrefs

Programs

Formula

a(n) = n * A001651(n).
a(n) = A000326(n) - A142150(n).
a(2*n) = A033579(n) = 4 * A000326(n);
a(2*n+1) = A033570(n) = A000326(2*n+1).
G.f.: x*(1+3*x+6*x^2+2*x^3)/((1+x)^2*(1-x)^3). - Bruno Berselli, Jul 09 2012
a(n) = A182079(3n). - Bruno Berselli, Jul 09 2012
From Amiram Eldar, Feb 18 2022: (Start)
Sum_{n>=1} 1/a(n) = Pi/(4*sqrt(3)) + 9*log(3)/4 - 2*log(2).
Sum_{n>=1} (-1)^(n+1)/a(n) = sqrt(3)*Pi/4 + 3*log(3)/4 - 2*log(2). (End)

A003141 Minimal number of arcs whose reversal yields a transitive tournament.

Original entry on oeis.org

0, 0, 0, 1, 1, 3, 4, 7, 8, 12, 15, 20, 22, 28
Offset: 0

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Author

Keywords

Comments

This is the "minimum feedback arc set" problem.
The minimal number of arcs you need to delete to make a directed graph acyclic (maxed over all n-vertex directed graphs) is the same as the minimal number of arcs you need to reverse to make a tournament acyclic (maxed over all n-player tournaments).

References

  • Sanchez-Flores, Neumann-Lara and Bermond, Graphs & Combin 10 (1994) 363-366 and 367-376.
  • N. J. A. Sloane and Simon Plouffe, The Encyclopedia of Integer Sequences, Academic Press, 1995 (includes this sequence).

Crossrefs

Equals C(n, 2) - A001225.
a(n) = A182079(n) iff n <= 9, thereafter a(n) > A182079(n). [Bermond]

Formula

The asymptotics for large n are (n+1)*n/4 - C*n^(3/2) <= F(n) <= (n+1)*n/4 - K*n^(3/2) for all sufficiently large n and certain constants C, K > 0. - Warren D. Smith, Sep 14 2006

Extensions

More terms from Irène Charon and Olivier Hudry
Terms a(12) and a(13) from Christian Stricker, Jan 14 2017
Showing 1-2 of 2 results.