A182210 Triangle T(n,k) = floor(k*(n+1)/(k+1)), 1 <= k <= n.
1, 1, 2, 2, 2, 3, 2, 3, 3, 4, 3, 4, 4, 4, 5, 3, 4, 5, 5, 5, 6, 4, 5, 6, 6, 6, 6, 7, 4, 6, 6, 7, 7, 7, 7, 8, 5, 6, 7, 8, 8, 8, 8, 8, 9, 5, 7, 8, 8, 9, 9, 9, 9, 9, 10, 6, 8, 9, 9, 10, 10, 10, 10, 10, 10, 11, 6, 8, 9, 10, 10, 11, 11, 11, 11, 11, 11, 12, 7, 9, 10, 11, 11, 12, 12, 12, 12, 12, 12, 12, 13, 7, 10, 11, 12, 12, 12, 13, 13, 13, 13, 13, 13, 13, 14, 8, 10, 12, 12, 13, 13, 14, 14, 14, 14, 14, 14, 14, 14, 15
Offset: 1
Examples
T(12,4) = 10 since 10 is the maximum number of wins in a 12-game sequence in which the longest winning streak is 4. One such sequence with 10 wins is WWWWLWWWWLWW. The triangle T(n,k) begins 1, 1, 2, 2, 2, 3, 2, 3, 3, 4, 3, 4, 4, 4, 5, 3, 4, 5, 5, 5, 6, 4, 5, 6, 6, 6, 6, 7, 4, 6, 6, 7, 7, 7, 7, 8, 5, 6, 7, 8, 8, 8, 8, 8, 9, 5, 7, 8, 8, 9, 9, 9, 9, 9, 10, 6, 8, 9, 9, 10, 10, 10, 10, 10, 10, 11, 6, 8, 9, 10, 10, 11, 11, 11, 11, 11, 11, 12,
Links
- Reinhard Zumkeller, Rows n = 1..150 of triangle, flattened
- Sela Fried and Toufik Mansour, The total number of descents and levels in (cyclic) tensor words, Disc. Math. Lett. (2024) Vol. 13, 44-49. See p. 49.
Crossrefs
A004523(n+1) = T(n,2).
Programs
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Haskell
a182210 n k = a182210_tabl !! (n-1) !! (k-1) a182210_tabl = [[k*(n+1) `div` (k+1) | k <- [1..n]] | n <- [1..]] -- Reinhard Zumkeller, Jul 08 2012
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Maple
seq(seq(floor(k*(n+1)/(k+1)),k=1..n),n=1..15);
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Mathematica
Flatten[Table[Floor[k*(n+1)/(k+1)],{n,0,20},{k,n}]] (* Harvey P. Dale, Jul 21 2015 *)
Formula
T(n,k) = floor(k(n+1)/(k+1)).
Comments