A183226 Sum of digits of (2^n) in base 5, also sum of digits of (10^n) in base 5.
1, 2, 4, 4, 4, 4, 8, 4, 4, 8, 12, 12, 12, 12, 8, 12, 16, 20, 20, 20, 16, 12, 20, 24, 28, 20, 32, 32, 24, 32, 40, 40, 32, 24, 28, 32, 32, 40, 28, 36, 36, 40, 44, 40, 36, 40, 36, 44, 44, 44, 44, 48, 52, 52, 48, 56, 40, 56, 68, 60, 52, 52, 48, 60, 56, 64, 60, 48, 56, 60, 60, 64, 60, 60, 60, 64, 52, 48, 64, 68, 56, 80, 80
Offset: 0
Examples
a(9) = 8 because 10^9 = 4022000000000_5, and 2^9 = 512 = 4022_5.
Links
- Robert Israel, Table of n, a(n) for n = 0..10000
Programs
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Maple
a:= n-> add(i, i=convert (2^n, base, 5)): seq(a(n), n=0..82); # Alois P. Heinz, Jan 06 2011
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Mathematica
Table[Plus@@IntegerDigits[2^n, 5], {n, 0, 49}] (* Either that one or this one *) Table[Plus@@IntegerDigits[10^n, 5], {n, 0, 49}] (* Alonso del Arte, Jan 06 2011 *)
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PARI
\\ L is the list of the N digits of 2^n in quinary. \\ L[1] = a_0 , ..., L[N] = a_(N-1). convert(n)={n=2^n; x=n; N=floor(log(n)/log(5))+1; L = listcreate(N); while(x, n=floor(n/5); r=x-5*n; listput(L, r); x=n; ); L; N}; for(n=0,100,convert(n);an=0;for(i=1,N,an+=L[i];); print1(an,", "));
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PARI
t(n) = if(n<1, 0, if(n%5, t(n-1)+1, t(n/5))); vector(200, n, n--; t(2^n)) \\ Altug Alkan, Oct 28 2015
Comments