A183565 Number of partitions of n containing a clique of size 8.
1, 0, 1, 1, 2, 2, 4, 4, 8, 9, 13, 16, 24, 28, 40, 49, 66, 82, 110, 132, 175, 214, 274, 336, 428, 520, 655, 798, 990, 1203, 1486, 1793, 2200, 2653, 3227, 3880, 4701, 5622, 6779, 8092, 9701, 11546, 13793, 16355, 19466, 23029, 27290, 32199, 38048, 44752, 52719
Offset: 8
Keywords
Examples
a(12) = 2, because 2 partitions of 12 contain (at least) one clique of size 8: [1,1,1,1,1,1,1,1,2,2], [1,1,1,1,1,1,1,1,4].
Links
- Alois P. Heinz, Table of n, a(n) for n = 8..1000
Crossrefs
Programs
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Maple
b:= proc(n, i) option remember; `if`(n=0, [1, 0], `if`(i<1, [0, 0], add((l->`if`(j=8, [l[1]$2], l))(b(n-i*j, i-1)), j=0..n/i))) end: a:= n-> (l-> l[2])(b(n, n)): seq(a(n), n=8..60);
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Mathematica
max = 60; f = (1 - Product[1 - x^(8j) + x^(9j), {j, 1, max}])/Product[1 - x^j, {j, 1, max}]; s = Series[f, {x, 0, max}]; Drop[CoefficientList[s, x], 8] (* Jean-François Alcover, Oct 01 2014 *) c8[n_]:=If[MemberQ[Tally[n][[All,2]],8],1,0]; Table[Total[c8/@ IntegerPartitions[ x]],{x,8,60}] (* Harvey P. Dale, Aug 12 2018 *)
Formula
G.f.: (1-Product_{j>0} (1-x^(8*j)+x^(9*j))) / (Product_{j>0} (1-x^j)).
Comments