A185679 Number of digits in decimal expansion of n^2.

1, 1, 1, 1, 2, 2, 2, 2, 2, 2, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 5

Offset: 0

Author

Carmine Suriano, Feb 23 2011

Keywords

• nonn
• base

Examples

			a(33)=4 since 33^2=1089 has 4 digits.
		

Links

• G. C. Greubel, Table of n, a(n) for n = 0..5000

Crossrefs

Cf. A055642.

Programs

Mathematica

Table[Length[IntegerDigits[n^2]], {n, 0, 100}]
Join[{1},IntegerLength[Range[100]^2]] (* Harvey P. Dale, Sep 17 2019 *)

PARI

concat([1], for(n=1,50, print1(1 + floor(log(n^2)/log(10)), ", "))) \\ G. C. Greubel, Jul 10 2017

Python

def A185679(n): return len(str(n**2)) # Chai Wah Wu, Mar 15 2023

Formula

a(n) = 1 + floor(log(10, n^2)) for n>0.