A188816 Triangle read by rows: row n gives (coefficients * (n-1)!) in expansion of pieces k=0..n-1 of the probability mass function for the Irwin-Hall distribution, lowest powers first.
1, 0, 1, 2, -1, 0, 0, 1, -3, 6, -2, 9, -6, 1, 0, 0, 0, 1, 4, -12, 12, -3, -44, 60, -24, 3, 64, -48, 12, -1, 0, 0, 0, 0, 1, -5, 20, -30, 20, -4, 155, -300, 210, -60, 6, -655, 780, -330, 60, -4, 625
Offset: 1
Examples
For n = 4, k = 1 (four variables, second piece) the function is the polynomial: 1/6 * (4 - 12x + 12x^2 -3x^3). That gives the subsequence [4, -12, 12, -3]. Triangle begins: [1]; [0,1], [2,-1]; [0,0,1], [-3,6,-2], [9,-6,1]; ...
Links
- Alois P. Heinz, Rows n = 1..32, flattened
- Philip Hall, The Distribution of Means for Samples of Size N Drawn from a Population in which the Variate Takes Values Between 0 and 1, All Such Values Being Equally Probable, Biometrika, Vol. 19, No. 3/4. (Dec., 1927), pp. 240-245.
- Wikipedia, Irwin-Hall distribution
Crossrefs
Differentiation of A188668.
Programs
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Maple
f:= proc(n, k) option remember; add((-1)^j * binomial(n, j) * (x-j)^(n-1), j=0..k) end: T:= (n, k)-> seq(coeff(f(n, k), x, t), t=0..n-1): seq(seq(T(n, k), k=0..n-1), n=1..7); # Alois P. Heinz, Jul 06 2017
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Mathematica
f[n_, k_] := f[n, k] = Sum[(-1)^j Binomial[n, j] (x-j)^(n-1), {j, 0, k}]; T[n_, k_] := Table[Coefficient[f[n, k], x, t], {t, 0, n-1}]; Table[Table[T[n, k], {k, 0, n-1}], {n, 1, 7}] // Flatten (* Jean-François Alcover, Feb 19 2021, after Alois P. Heinz *)
Formula
G.f. for piece k in row n: (1/(n-1)!) * Sum_{j=0..k} (-1)^j * C(n,j) * (x-j)^(n-1).
Comments