cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

A192442 Coefficient of x^n in the expansion of (1+x^3+x^4)^n.

Original entry on oeis.org

1, 0, 0, 3, 4, 0, 15, 42, 28, 84, 360, 495, 715, 2860, 6006, 8463, 23660, 61880, 104244, 220932, 596904, 1201560, 2313003, 5753979, 12983707, 25477100, 57557500, 135227235, 280913490, 600900300, 1395727515, 3046800900, 6447717900, 14540497920, 32572229976, 69844899432
Offset: 0

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Author

Joerg Arndt, Jul 01 2011

Keywords

Crossrefs

Programs

  • Magma
    P:=PolynomialRing(Integers()); [ Coefficients((1+x^3+x^4)^n)[ n+1 ]: n in [0..40] ]; // Vincenzo Librandi, Sep 10 2011
    
  • Mathematica
    Table[Coefficient[(1+x^3+x^4)^n, x, n],{n,0,20}] (* Vaclav Kotesovec, Jun 15 2014 *)
  • Maxima
    makelist((coeff(expand((1+x^3+x^4)^n), x, n)), n, 0, 40); /* Vincenzo Librandi, Sep 10 2011 */
    
  • Maxima
    a(n):=sum(binomial(j,n-3*j)*binomial(n,j),j,floor(n/4),floor(n/3)); /* Vladimir Kruchinin, Jun 14 2014 */
  • PARI
    a(n)=polcoeff((1+x^3+x^4)^n,n);
    
  • PARI
    {a(n)=local(G=(1/x)*serreverse(x/(1+x^3+x^4 +x^2*O(x^n))));polcoeff(1+x*G'/G, n)} \\ Paul D. Hanna, Jun 14 2014
    for(n=0,30,print1(a(n),", "))
    

Formula

Recurrence: 3*n*(3*n-2)*(3*n-1)*(115668*n^3 - 650916*n^2 + 1167723*n - 673723)*a(n) = 2*(n-1)*(231336*n^5 - 1417500*n^4 + 3231306*n^3 - 3349145*n^2 + 1574119*n - 264960)*a(n-1) - 6*(n-2)*(n-1)*(115668*n^4 - 535248*n^3 + 861921*n^2 - 529129*n + 122640)*a(n-2) + 24*(n-2)*(n-1)*(925344*n^4 - 4744656*n^3 + 7608276*n^2 - 4369418*n + 755115)*a(n-3) + 229*(n-3)*(n-2)*(n-1)*(115668*n^3 - 303912*n^2 + 212895*n - 41248)*a(n-4). - Vaclav Kotesovec, Apr 21 2014
a(n) = sum(j=floor(n/4)..floor(n/3), binomial(j,n-3*j)*binomial(n,j)). - Vladimir Kruchinin, Jun 14 2014
G.f.: 1 + x*G'(x)/G(x) where G(x) = 1 + x^3*G(x)^3 + x^4*G(x)^4 = (1/x)*Series_Reversion(x/(1+x^3+x^4)). - Paul D. Hanna, Jun 14 2014