A194202 a(n) = [Sum_{k=1..n} (2k*e)], where [ ]=floor, ( )=fractional part.
0, 1, 1, 2, 2, 3, 3, 3, 4, 5, 5, 6, 6, 6, 7, 8, 8, 9, 9, 10, 10, 11, 11, 11, 12, 13, 14, 14, 14, 15, 15, 16, 16, 17, 18, 18, 18, 19, 19, 19, 20, 21, 21, 22, 22, 22, 23, 24, 24, 25, 25, 26, 26, 27, 27, 27, 28, 28, 29, 29, 30, 30, 31, 32, 32, 33, 33, 34, 34, 34, 35, 36, 37
Offset: 1
Keywords
Links
- G. C. Greubel, Table of n, a(n) for n = 1..5000
Crossrefs
Cf. A194203.
Programs
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Mathematica
r = 2E; a[n_] := Floor[Sum[FractionalPart[k*r], {k, 1, n}]] Table[a[n], {n, 1, 90}] (* A194202 *) s[n_] := Sum[a[k], {k, 1, n}] Table[s[n], {n, 1, 100}] (* A194203 *) Floor[Accumulate[FractionalPart[2 Range[80]E]]] (* Harvey P. Dale, Aug 16 2021 *)
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PARI
a(n) = floor(sum(k=1, n, frac(2*exp(1)*k))); \\ Michel Marcus, Nov 12 2017
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