A202708 Sum of digits of n! divided by 9.
1, 1, 1, 3, 3, 4, 3, 3, 5, 5, 7, 7, 6, 5, 6, 7, 8, 11, 9, 8, 9, 12, 10, 14, 13, 15, 12, 16, 16, 16, 19, 17, 12, 21, 21, 16, 21, 20, 24, 23, 24, 25, 26, 25, 24, 22, 31, 31, 29, 31, 37, 30, 32, 36, 32, 35, 34, 37, 36, 39, 39, 41, 38, 39, 51, 47, 48, 35, 42, 48
Offset: 6
Links
- Seiichi Manyama, Table of n, a(n) for n = 6..10000
Programs
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Mathematica
Table[Sum[DigitCount[n!][[i]]*i/9, {i, 1, 9}], {n, 6, 100}] Total[IntegerDigits[#]]/9&/@(Range[6,80]!) (* Harvey P. Dale, Nov 22 2023 *)
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PARI
a(n) = sumdigits(n!)/9; \\ Michel Marcus, Aug 12 2022
Formula
a(n) = A004152(n)/9.
Comments