A064692 Total number of holes in decimal expansion of the number n, assuming 4 has 1 hole.
1, 0, 0, 0, 1, 0, 1, 0, 2, 1, 1, 0, 0, 0, 1, 0, 1, 0, 2, 1, 1, 0, 0, 0, 1, 0, 1, 0, 2, 1, 1, 0, 0, 0, 1, 0, 1, 0, 2, 1, 2, 1, 1, 1, 2, 1, 2, 1, 3, 2, 1, 0, 0, 0, 1, 0, 1, 0, 2, 1, 2, 1, 1, 1, 2, 1, 2, 1, 3, 2, 1, 0, 0, 0, 1, 0, 1, 0, 2, 1, 3, 2, 2, 2, 3, 2, 3, 2, 4, 3, 2, 1, 1, 1, 2, 1, 2, 1, 3, 2, 2, 1, 1, 1, 2
Offset: 0
Examples
We assume decimal digits 1,2,3,5,7 have no hole; 0,4,6,9 have one hole each; 8 has two holes. So a(148)=3.
Links
- Indranil Ghosh, Table of n, a(n) for n = 0..50000
Programs
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Mathematica
Table[DigitCount[x].{0, 0, 0, 1, 0, 1, 0, 2, 1, 1}, {x, 0, 104}] (* Zak Seidov, Jul 25 2015 *) -
Python
def A064692(n): x=str(n) return x.count("0")+x.count("4")+x.count("6")+x.count("8")*2+x.count("9") # Indranil Ghosh, Feb 02 2017
Formula
a(A001742(n)) = 0. - Michel Marcus, Jul 25 2015
Comments