cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

A226122 Expansion of (1+2*x+x^2+x^3+2*x^4+x^5)/(1-2*x^3+x^6).

Original entry on oeis.org

1, 2, 1, 3, 6, 3, 5, 10, 5, 7, 14, 7, 9, 18, 9, 11, 22, 11, 13, 26, 13, 15, 30, 15, 17, 34, 17, 19, 38, 19, 21, 42, 21, 23, 46, 23, 25, 50, 25, 27, 54, 27, 29, 58, 29, 31, 62, 31, 33, 66, 33, 35, 70, 35, 37, 74, 37, 39, 78, 39
Offset: 0

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Author

Paul Curtz, May 27 2013

Keywords

Comments

A226023 (starting from A226023(-2)=0) and successive differences:
0, -1, 0, 2, 3, 6, 12, 15, 20, 30,...
-1, 1, 2, 1, 3, 6, 3, 5, 10, 5,... = a(n-1)
2, 1, -1, 2, 3, -3, 2, 5, -5, 2,...
-1, -2, 3, 1, -6, 5, 3, -10, 7, 5,...
-1, 5, -2, -7, 11, -2, -13, 17, -2, -19,...
6, -7, -5, 18, -13, -11, 30, -19, -17, 42,...
-13, 2, 23, -31, 2, 41, -49, 2, 59, 67,...
15, 21, -54, 33, 39, -90, 51, 57, -126, 69,... multiples of 3
6, -75, 87, 6, -129, 141, 6, -183, 195, 6,... multiples of 3
-81, 162, -81, -135, 270, -135, -189, 378, -189, -243,... multiples of 27
The last line is -27*a(n+3)*A131561(n+1).
The recurrences in the Formula field hold for the array.

Examples

			Given A130823 = 1,1,1,3,3,3,5,5,5,7,7,7,... and A131534 = 1,2,1,1,2,1,1,2,1,1,2,1,..., then a(0)=1*1=1, a(1)=1*2=2, a(2)=1*1=1, a(3)=3*1=3, a(4)=3*2=6, etc.
Given A226023(n) from A226023(-1)=-1, then a(0)=0-(-1)=1, a(1)=2-0=2, a(2)=3-2=1, a(3)=6-3=3, a(4)=12-6=6, etc.
		

Crossrefs

Programs

  • Mathematica
    repeat=20; Table[{1, 2, 1}, {repeat}]*(2*Range[repeat]-1) // Flatten
    (* or *) Table[Floor[(2*n+1)/3]*Floor[(2*n+5)/3], {n, -1, 59}] // Differences (* Jean-François Alcover, May 29 2013 *)

Formula

a(n) = A130823(n-1) * A131534(n).
a(n) = A226023(n) - A226023(n-1) with A226023(-1)=-1.
a(n) = 3*a(n-3) -3*a(n-6) +a(n-9) = a(n-1) +2*a(n-3) -2*a(n-4) -a(n-6) +a(n-7). [Ralf Stephan]
From Bruno Berselli, May 29 2013: (Start)
G.f.: (1+x)^3*(1-x+x^2)/((1-x)^2*(1+x+x^2)^2).
a(n) = 2*a(n-3)-a(n-6).
a(3n)*a(3n-1)-a(3n-2) = A016754(n-1), n>0. (End)