A229903 -id:A229903 - cp's OEIS frontend

A097647 Non-palindromic numbers n such that phi(n) = phi(reversal(n)).

190, 427, 429, 724, 924, 4147, 4697, 6276, 6726, 7414, 7964, 9079, 9709, 10040, 10940, 14450, 15860, 19190, 20493, 20553, 28092, 28215, 29082, 35502, 39402, 41847, 42777, 44629, 46899, 49929, 51282, 51845, 53075, 54815, 57035, 57677

Offset: 1

Farideh Firoozbakht, Aug 28 2004

If n is in the sequence and 10 doesn't divide n then reversal(n) is also in the sequence. There exists three terms of this sequence less than 180000000 that reversal of them are primes,i.e. 10040,14450 and 1865170. This sequence has 445 composite terms less than 20000000 and there is no prime term up to 222000000. Has this sequence at least one prime term?
(190/99)*(100^m-1) is in the sequence iff 3 does not divide m (m is a term of A001651). So the sequence is infinite. A229903: 190, 19190, 191919190, 19191919190, ...  are such terms. - Jahangeer Kholdi, Oct 17 2013
There are no prime terms < 10^10. - Donovan Johnson, Oct 18 2013

			10040 is in the sequence because phi(10040)=phi(4001)=4000.

Cf. A097648, A085329.

Cf. A001651, A229903.

Do[If[n!=FromDigits[Reverse[IntegerDigits[n]]]&&EulerPhi[n]==EulerPhi[ FromDigits[Reverse[IntegerDigits[n]]]], Print[n]], {n, 80000}]

cp's OEIS Frontend

A097647 Non-palindromic numbers n such that phi(n) = phi(reversal(n)).

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