cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

Showing 1-2 of 2 results.

A233527 Decimal expansion of arctan( 1/(2*Pi) ): opposite angle for a right triangle of equal area to a circle.

Original entry on oeis.org

1, 5, 7, 8, 3, 1, 1, 9, 0, 2, 8, 8, 1, 5, 8, 8, 6, 0, 1, 6, 7, 6, 0, 8, 7, 4, 1, 7, 8, 2, 8, 1, 8, 9, 2, 3, 6, 0, 5, 0, 7, 1, 2, 4, 0, 5, 9, 9, 0, 5, 1, 0, 6, 0, 4, 1, 5, 5, 5, 7, 9, 6, 7, 2, 1, 3, 8, 2, 2, 1, 1, 9, 5, 6, 5, 1, 8, 2, 1, 0, 9, 1, 6, 0, 5, 8, 7, 1, 3, 9, 4, 4, 0, 8, 0, 3, 1, 4, 0, 0
Offset: 0

Views

Author

John W. Nicholson, Dec 11 2013

Keywords

Examples

			0.15783119028815886016760874178281892360507124059905106041555796721382...
		

Crossrefs

Programs

  • Mathematica
    RealDigits[ArcTan[1/(2 Pi)], 10, 110][[1]] (* Bruno Berselli, Dec 16 2013 *)
  • PARI
    atan(1/(2*Pi))

Formula

Equals arctan(1/A019692).
Equals A019669 - A233528. [Bruno Berselli, Dec 16 2013]

Extensions

More terms from Ralf Stephan, Dec 16 2013

A233700 Decimal expansion of 1/sin(arctan(1/t)) or t/sin(arctan(t)) where t = 2*Pi: hypotenuse for a right triangle of equal area to a disk.

Original entry on oeis.org

6, 3, 6, 2, 2, 6, 5, 1, 3, 1, 5, 6, 7, 3, 2, 8, 3, 9, 3, 6, 9, 1, 2, 4, 5, 4, 4, 0, 5, 8, 6, 8, 0, 4, 4, 1, 0, 6, 9, 9, 7, 1, 4, 9, 8, 5, 1, 3, 8, 9, 8, 9, 6, 8, 6, 5, 8, 2, 0, 4, 1, 6, 1, 7, 0, 4, 5, 9, 9, 8, 5, 8, 7, 3, 3, 1, 7, 8, 4, 8, 5, 4, 1, 3, 4, 5, 5, 0, 8, 7, 7, 1, 3
Offset: 1

Views

Author

John W. Nicholson, Dec 16 2013

Keywords

Comments

"The great mathematician Archimedes used the tools of Euclidean geometry to show that the area inside a circle is equal to that of a right triangle whose base has the length of the circle's circumference and whose height equals the circle's radius in his book Measurement of a Circle." (Quote from Wikipedia link)

Examples

			6.362265131567328393691245440586804410699714985138989686582041617045998587331...
		

Crossrefs

Programs

  • Julia
    using Nemo
    RR = RealField(310)
    t = const_pi(RR) + const_pi(RR)
    t/sin(atan(t)) |> println # Peter Luschny, Mar 13 2018
  • Magma
    C := ComplexField(); Sqrt(1 + 4*Pi(C)^2) // G. C. Greubel, Jan 08 2018
    
  • Magma
    R:=RealField(110); SetDefaultRealField(R); n:=Sqrt(1+4*Pi(R)^2); Reverse(Intseq(Floor(10^108*n))); // Bruno Berselli, Mar 13 2018
    
  • Mathematica
    RealDigits[(2*Pi)/Sin[ArcTan[2*Pi]],10,120][[1]] (* Harvey P. Dale, Jul 12 2014 *)
    RealDigits[ Sqrt[1 + 4*Pi^2], 10, 111][[1]] (* Robert G. Wilson v, Mar 12 2015 *)
  • PARI
    sqrt(1+(2*Pi)^2)
    

Formula

Equals sqrt(1+(2*Pi)^2) = sqrt(1 + (A019692)^2) = sqrt(1 + A212002) = 1/sin(A233527) = A019692/sin(A233528) = 1/cos(A233528) = A019692/cos(A233527).
Showing 1-2 of 2 results.