cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

Showing 1-5 of 5 results.

A239066 Triangle read by rows: row n lists the smallest positive ideal multigrade of degree n, or 2n+2 zeros if none.

Original entry on oeis.org

1, 3, 2, 2, 1, 4, 4, 2, 2, 5, 1, 4, 5, 8, 2, 2, 7, 7, 1, 5, 9, 17, 18, 2, 3, 11, 15, 19, 1, 4, 6, 12, 14, 17, 2, 2, 9, 9, 16, 16, 1, 19, 20, 51, 57, 80, 82, 2, 12, 31, 40, 69, 71, 85, 1, 5, 10, 24, 28, 42, 47, 51, 2, 3, 12, 21, 31, 40, 49, 50, 1, 25, 31, 84, 87, 134, 158, 182, 198, 2, 18, 42, 66, 113, 116, 169, 175, 199, 1, 13, 126, 214, 215, 413, 414, 502, 615, 627, 6, 7, 134, 183, 243, 385, 445, 494, 621, 622
Offset: 1

Views

Author

Jonathan Sondow, Mar 09 2014

Keywords

Comments

Each row begins with 1 or 0. The n-th row has 2n+2 terms.
A "positive multigrade of degree n" and size s is a pair of distinct multisets of positive integers x1 <= x2 <= ... <= xs; y1 <= y2 <= ... <= ys such that x1^k + x2^k + ... + xs^k = y1^k + y2^k + ... + ys^k for k=1,2,...,n. A multigrade is "ideal" if s=n+1 (the smallest possible size for a multigrade of degree n).
Ideal multigrades are known only for degrees < 11 and degree 12. The ideal multigrades of degrees 5,6,7,8,9,10 are only conjecturally the smallest ones.
A multigrade is a solution of the Prouhet-Tarry-Escott problem.
For symmetric and non-symmetric multigrades, see A239067 and A239068.

Examples

			1, 3; 2, 2
1, 4, 4; 2, 2, 5
1, 4, 5, 8; 2, 2, 7, 7
1, 5, 9, 17, 18; 2, 3, 11, 15, 19
1, 4, 6, 12, 14, 17; 2, 2, 9, 9, 16, 16
1, 19, 20, 51, 57, 80, 82; 2, 12, 31, 40, 69, 71, 85
1, 5, 10, 24, 28, 42, 47, 51; 2, 3, 12, 21, 31, 40, 49, 50
1, 25, 31, 84, 87, 134, 158, 182, 198; 2, 18, 42, 66, 113, 116, 169, 175, 199
1, 13, 126, 214, 215, 413, 414, 502, 615, 627; 6, 7, 134, 183, 243, 385, 445, 494, 621, 622
1, 4, 4; 2, 2, 5 is an ideal multigrade of degree 2 as 1^1 + 4^1 + 4^1 = 9 = 2^1 + 2^1 + 5^1 and 1^2 + 4^2 + 4^2 = 33 = 2^2 + 2^2 + 5^2.
		

References

  • A. H. Beiler, Recreations in the Theory of Numbers, Dover, NY, 1964, pp. 162-165.
  • L. E. Dickson, History of the theory of numbers, vol. II: Diophantine Analysis, reprint, Chelsea, New York, 1966, pp. 705-716.
  • R. K. Guy, Unsolved Problems in Number Theory, D1.
  • G. H. Hardy and E. M. Wright, "The Four-Square Theorem" and "The Problem of Prouhet and Tarry: The Number P(k,j)." §20.5 and 21.9 in An Introduction to the Theory of Numbers, 5th ed. Oxford, England: Clarendon Press, pp. 302-306 and 328-329, 1979.

Crossrefs

Cf. A362039 (for a related problem with sets of primes instead of multisets of positive integers).

Formula

a(n^2 + n - 1) = 1 or 0.

A239067 Triangle read by rows: row n lists the smallest positive ideal symmetric multigrade of degree n, or 2n+2 zeros if none.

Original entry on oeis.org

1, 3, 2, 2, 1, 4, 4, 2, 2, 5, 1, 4, 5, 8, 2, 2, 7, 7, 1, 5, 9, 17, 18, 2, 3, 11, 15, 19, 1, 4, 6, 12, 14, 17, 2, 2, 9, 9, 16, 16, 1, 19, 28, 59, 65, 90, 102, 2, 14, 39, 45, 76, 85, 103, 1, 5, 10, 24, 28, 42, 47, 51, 2, 3, 12, 21, 31, 40, 49, 50, 1, 25, 31, 84, 87, 134, 158, 182, 198, 2, 18, 42, 66, 113, 116, 169, 175, 199, 1, 13, 126, 214, 215, 413, 414, 502, 615, 627, 6, 7, 134, 183, 243, 385, 445, 494, 621, 622
Offset: 1

Views

Author

Jonathan Sondow, Mar 10 2014

Keywords

Comments

The main entry for this topic is A239066.
A multigrade x1<=x2<=...<=xs; y1<=y2<=...<=ys is "symmetric" if x1+ys = x2+y(s-1) = ... = xs+y1 when s is odd, or x1+xs = x2+x(s-1) = ... = x(s/2)+x((s/2)+1) = y1+ys = y2+y(s-1) = ... = y(s/2)+y((s/2)+1) when s is even. For non-symmetric ones, see A239068.
The ideal symmetric multigrades of degrees 5,6,7,8,9,10 are only conjecturally the smallest ones.

Examples

			1, 3; 2, 2
1, 4, 4; 2, 2, 5
1, 4, 5, 8; 2, 2, 7, 7
1, 5, 9, 17, 18; 2, 3, 11, 15, 19
1, 4, 6, 12, 14, 17; 2, 2, 9, 9, 16, 16
1, 19, 28, 59, 65, 90, 102; 2, 14, 39, 45, 76, 85, 103
1, 5, 10, 24, 28, 42, 47, 51; 2, 3, 12, 21, 31, 40, 49, 50
1, 25, 31, 84, 87, 134, 158, 182, 198; 2, 18, 42, 66, 113, 116, 169, 175, 199
1, 13, 126, 214, 215, 413, 414, 502, 615, 627; 6, 7, 134, 183, 243, 385, 445, 494, 621, 622
1, 4, 4; 2, 2, 5 is an ideal symmetric multigrade of degree 2 as 1+5 = 4+2 = 4+2 and 1^1 + 4^1 + 4^1 = 9 = 2^1 + 2^1 + 5^1 and 1^2 + 4^2 + 4^2 = 33 = 2^2 + 2^2 + 5^2.
1, 4, 5, 8; 2, 2, 7, 7 is an ideal symmetric multigrade of degree 3 as 1+8 = 4+5 = 2+7 = 2+7 and 1^1 + 4^1 + 5^1 + 8^1 = 18 = 2^1 + 2^1 + 7^1 + 7^1 and 1^2 + 4^2 + 5^2 + 8^2 = 106 = 2^2 + 2^2 + 7^2 + 7^2 and 1^3 + 4^3 + 5^3 + 8^3 = 702 = 2^3 + 2^3 + 7^3 + 7^3.
		

Crossrefs

Formula

a(n^2 + n - 1) = 1 or 0.

A237434 Primitive, symmetric octuples of distinct numbers a,b,c,d,x,y,z,w with 0

Original entry on oeis.org

1, 5, 8, 12, 2, 3, 10, 11, 1, 8, 10, 17, 2, 5, 13, 16, 1, 10, 12, 23, 3, 5, 16, 22
Offset: 1

Views

Author

Jonathan Sondow, Feb 07 2014

Keywords

Comments

If a,b,c,d,x,y,z,w satisfies the (in)equalities in the definition, then so does the translate a-t,b-t,c-t,d-t,x-t,y-t,z-t,w-t, for t
Bennett, Minculete, and Tetiva show that there do not exist distinct numbers a,b,c,x,y,z with 0
In this 6-term multigrade problem, if the restriction a<=x

Examples

			1 + 5 + 8 + 12 = 26 = 2 + 3 + 10 + 11.
1^2 + 5^2 + 8^2 + 12^2 = 234 = 2^2 + 3^2 + 10^2 + 11^2.
1^3 + 5^3 + 8^3 + 12^3 = 2366 = 2^3 + 3^3 + 10^3 + 11^3.
1 + 12 = 5 + 8 = 2 + 11 = 3 + 10 = 13.
		

References

  • A. H. Beiler, Recreations in the Theory of Numbers, Dover, NY, 1964, pp. 162-165.
  • L. E. Dickson, History of the theory of numbers, vol. II: Diophantine Analysis, reprint, Chelsea, New York, 1966, pp. 705-716.
  • R. K. Guy, Unsolved Problems in Number Theory, D1.

Crossrefs

A237435 Analog of A237434 for 16-tuples.

Original entry on oeis.org

1, 5, 10, 24, 28, 42, 47, 51, 2, 3, 12, 21, 31, 40, 49, 50
Offset: 1

Author

Jonathan Sondow, Feb 08 2014

Keywords

Comments

See A237434 for comments, references, and links.

Examples

			1^k + 5^k + 10^k + 24^k + 28^k + 42^k + 47^k + 51^k =
2^k + 3^k + 12^k + 21^k + 31^k + 40^k + 49^k + 50^k =
208, 8060, 347464, 15713636, 730337608, 34538543780, 1652662609624,
for k = 1,2,3,4,5,6,7, respectively.
1+51 = 5+47 = 10+42 = 24+28 = 2+50 = 3+49 = 12+40 = 21+31 = 52.
		

Crossrefs

A362039 Least number s such that there are 2 different sets of primes { a1, a2, ..., an } and { b1, b2, ..., bn } with the integers in each set having the same sum s, the same sum of squares, etc., up to and including the same sum of (n-1)-st powers.

Original entry on oeis.org

16, 55, 120, 433, 378
Offset: 2

Author

Jean-Marc Rebert, Apr 15 2023

Keywords

Comments

We are to find the least number s such that there is a solution in primes to the system of equations:
a1^k + a2^k + ... + an^k = b1^k + b2^k + ... + bn^k, (k = 1, 2, ..., n-1) and {a1, ..., an} != {b1, ..., bn}.
a(7), a(8) are respectively <= 2399, 348592.

Examples

			a(2) = 16, because 3 + 13 = 16 = 5 + 11 and no lesser sum of 2 distinct primes has this property.
a(3) = 55, because 7 + 19 + 29 = 55 = 11 + 13 + 31 and 7^2 + 19^2 + 29^2 = 1251 = 11^2 + 13^2 + 31^2, and no lesser sum of 3 distinct primes has this property.
a(4) = 120, because with u = [13, 29, 31, 47] and v = [17, 19, 41, 43], Sum_{i=1..4} u(i) = 120  = Sum_{i=1..4} v(i) and Sum_{i=1..4} u(i)^2 = 4100 = Sum_{i=1..4} v(i)^2 and Sum_{i=1..4} u(i)^3 = 1602000 = Sum_{i=1..4} v(i)^3 and no lesser sum of 4 distinct primes has this property.
From _Andrew Howroyd_, Apr 18 2023: (Start)
a(5) = 433 with {13, 59, 67, 131, 163} and {23, 31, 103, 109, 167}.
a(6) = 378 with {17, 37, 43, 83, 89, 109} and {19, 29, 53, 73, 97, 107}.
(End)
		

Programs

  • PARI
    \\ Call with pr=1 to also print solution sets.
    a(n, pr=0)={
      forstep(s=3*n, oo, 2, my(P=vector(s,i,primepi(i)), X=primes(P[s]));
        local(found=0, M=Map(), V=vector(n));
        my(onSet()=my(key=vector(n-2, j, sum(i=1, n, V[i]^(j+1))), z);
          if(mapisdefined(M,key,&z), found++; if(pr, print(V, z)), mapput(M,key,V)));
        my(recurse(r,m,k)=if(k==0, onSet(), for(m=max(k,P[(r-1)\k])+1, min(m, P[r-3*(k-1)]), V[k]=X[m]; self()(r-X[m], m-1, k-1)) ));
        recurse(s, #X, n);
        if(found, return(s));
      )
    } \\ Andrew Howroyd, Apr 18 2023

Formula

a(2) = min({k >= 1 : A117929(k) >= 2}) = Min_{m >= 2} A087747(m) = A087747(2). - Peter Munn, May 01 2023

Extensions

a(5)-a(6) from Andrew Howroyd, Apr 18 2023
Edited by Peter Munn, May 01 2023
Showing 1-5 of 5 results.