A054871
a(n) = H_n(3,2) where H_n is the n-th hyperoperator.
Original entry on oeis.org
3, 5, 6, 9, 27, 7625597484987
Offset: 0
a(0) = H_0(3,2) = 2+1 = 3;
a(1) = H_1(3,2) = 3+2 = 5;
a(2) = H_2(3,2) = 3*2 = 3+3 = 6;
a(3) = H_3(3,2) = 3^2 = 3*3 = 9;
a(4) = H_4(3,2) = 3^^2 = 3^3 = 27;
a(5) = H_5(3,2) = 3^^^2 = 3^^3 = 3^(3^3) = 7625597484987.
- John H. Conway and R. K. Guy, The Book of Numbers, Copernicus Press, p. 60.
- Rick Norwood, Math. Bite: Why 2 + 2 = 2 * 2, Mathematics Magazine, Vol. 71 (1998), p. 60.
- Stephen R. Wassell, Superexponentiation and Fixed Points of Exponential and Logarithmic Functions, Mathematics Magazine, Vol. 73 (2000), pp. 111-119.
- Eric Weisstein's MathWorld, Ackermann Function and Power Tower
- Wikipedia, Hyperoperation
- Index Section Ho-Hy
H_n(x,y) for various x,y:
A001695 (2,n), this sequence (3,2; almost 3,3),
A067652 (2,3; almost 2,4),
A141044 (1,1),
A175796 (n,2),
A179184 (0,0),
A189896 (n,n),
A213619 (n,H_n(n,n)),
A253855 (4,2; almost 4,4),
A255176 (2,2),
A255340 (4,3),
A256131 (10,2; almost 10,10),
A261143 (1,2),
A261146 (n,3). -
Natan Arie Consigli and
Danny Rorabaugh, Oct 14-26 2015
First term corrected and hyperoperator notation implemented by
Danny Rorabaugh, Oct 14 2015
A189896
Weak Ackermann numbers: H_n(n,n) where H_n is the n-th hyperoperator.
Original entry on oeis.org
a(0) = succ(0) = 0 + 1 = 1, because the zeroth hyperoperation is successor.
a(1) = 1 + 1 = 2, because the first hyperoperation is addition.
a(2) = 2 * 2 = 4, because the second hyperoperation is multiplication.
a(3) = 3^3 = 27, because the third hyperoperation is exponentiation.
a(4) = 4^4^4^4 = 4^(4^(4^4)) = 4^(4^256), because the fourth hyperoperation is tetration. The term is too big to be included: log_2(a(4)) = 2^513.
For H_n(x,x) with fixed x, cf.
A054871 (x=3, shifted),
A141044 (x=1),
A253855 (x=4, shifted),
A255176 (x=2),
A256131 (x=10, shifted). -
Danny Rorabaugh, Oct 20 2015
A175796
H_n(n, 2) where H_c(a, b) is the hyperoperation function with operator c.
Original entry on oeis.org
3, 3, 4, 9, 256
Offset: 0
a(0) = H_0(0, 2) = 2 + 1 = 3
a(1) = H_1(1, 2) = 1 + 2 = 3
a(2) = H_2(2, 2) = 2 * 2 = 4
a(3) = H_3(3, 2) = 3 ^ 2 = 9
a(4) = H_4(4, 2) = 4 ^^ 2 = 4 ^ 4 = 256
a(5) = H_5(5, 2) = 5 ^^^ 2 = 5 ^^ 5 = 5 ^ 5 ^ 5 ^ 5 ^ 5 =~ 10 ^ (10 ^ (10 ^ (2184.1257...)))
-
def H(a, b, c):
if c == 0: return b + 1
if c == 1 and b == 0: return a
if c == 2 and b == 0: return 0
if c >= 3 and b == 0: return 1
return H(a, H(a, b - 1, c), c - 1)
for n in range(5): print(H(n, 2, n))
A280265
Array with five columns read by rows: H_k(n,2), with rows n >= 0 and columns 0 <= k <= 4, where H_n is the n-th hyperoperation.
Original entry on oeis.org
3, 2, 0, 1, 1, 3, 3, 2, 1, 1, 3, 4, 4, 4, 4, 3, 5, 6, 9, 27, 3, 6, 8, 16, 256, 3, 7, 10, 25, 3125, 3, 8, 12, 36, 46656, 3, 9, 14, 49, 823543, 3, 10, 16, 64, 16777216, 3, 11, 18, 81, 387420489, 3, 12, 20, 100, 10000000000, 3, 13, 22, 121, 285311670611, 3, 14, 24, 144, 8916100448256
Offset: 0
Square array begins:
3, 2, 0, 1, 1;
3, 3, 2, 1, 1;
3, 4, 4, 4, 4;
3, 5, 6, 9, 27;
3, 6, 8, 16, 256;
3, 7, 10, 25, 3125;
3, 8, 12, 36, 46656;
3, 9, 14, 49, 823543;
3, 10, 16, 64, 16777216;
3, 11, 18, 81, 387420489;
3, 12, 20, 100, 10000000000;
3, 13, 22, 121, 285311670611;
3, 14, 24, 144, 8916100448256;
...
For row 10 we have:
H_0(10,2) = 3;
H_1(10,2) = 12;
H_2(10,2) = 20;
H_3(10,2) = 100;
H_4(10,2) = 10000000000;
-
H[0, x_, y_] := y + 1;
H[1, x_, y_] := x + y;
H[2, x_, y_] := x*y;
H[3, x_, y_] := x^y;
H[4, x_, 2] := x^x;
Table[H[k, n, 2], {n, 0, 20}, {k, 0, 4}]
Showing 1-4 of 4 results.
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