cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

Showing 1-4 of 4 results.

A164146 Number of binary strings of length n with equal numbers of 010 and 101 substrings.

Original entry on oeis.org

1, 2, 4, 6, 12, 20, 38, 66, 124, 224, 424, 788, 1502, 2838, 5438, 10386, 20004, 38508, 74516, 144264, 280216, 544736, 1061292, 2069596, 4042254, 7902294, 15466842, 30297422, 59404174, 116558270, 228876426, 449713994, 884199348, 1739434972, 3423770240, 6742430340
Offset: 0

Views

Author

R. H. Hardin, Aug 11 2009

Keywords

Examples

			a(5) = 20: 00000, 00001, 00011, 00101, 00110, 00111, 01011, 01100, 01110, 01111, 10000, 10001, 10011, 10100, 11000, 11001, 11010, 11100, 11110, 11111. - _Alois P. Heinz_, Apr 16 2015
		

Crossrefs

Column k=1 of A303696.
Column k=0 of A307796.

Programs

  • Mathematica
    CoefficientList[Series[-(4*x^4-2*x^3-2*x^2+x+Sqrt[(2*x-1)*(2*x^2-1)*(2*x^2-2*x+1)]) / ((x-1)*(2*x-1)*(2*x^2-1)),{x,0,33}],x] (* Stefano Spezia, Jul 31 2025 *)

Formula

G.f.: -(4*x^4-2*x^3-2*x^2+x+sqrt((2*x-1)*(2*x^2-1)*(2*x^2-2*x+1))) / ((x-1)*(2*x-1)*(2*x^2-1)). - Alois P. Heinz, Apr 16 2015

A260697 Number of binary words w of length n with equal numbers of 010 and 101 subwords such that for every prefix of w the number of occurrences of subword 101 is larger than or equal to the number of occurrences of subword 010.

Original entry on oeis.org

1, 2, 4, 6, 11, 18, 32, 54, 95, 164, 291, 514, 923, 1656, 3000, 5442, 9942, 18216, 33564, 62040, 115167, 214404, 400497, 750070, 1408734, 2652088, 5004833, 9464616, 17935137, 34049044, 64754844, 123351410, 235335966, 449632300, 860241606, 1647932000
Offset: 0

Views

Author

Alois P. Heinz, Nov 16 2015

Keywords

Examples

			a(3) = 6: 000, 001, 011, 100, 110, 111.
a(4) = 11: 0000, 0001, 0011, 0110, 0111, 1000, 1001, 1010, 1100, 1110, 1111.
a(5) = 18: 00000, 00001, 00011, 00110, 00111, 01100, 01110, 01111, 10000, 10001, 10011, 10100, 11000, 11001, 11010, 11100, 11110, 11111.
a(10) = 291: 0000000000, 0000000001, 0000000011, ..., 0110101010, 1010101000, 1010101001, 1010101010, 1101010100, 1110101010, ..., 1111111100, 1111111110, 1111111111.
		

Crossrefs

Programs

  • Maple
    b:= proc(n, t, c) option remember;
         `if`(c<0, 0, `if`(n=0, `if`(c=0, 1, 0),
          b(n-1, [2, 4, 6, 4, 6, 4, 6][t], c-`if`(t=5, 1, 0))+
          b(n-1, [3, 5, 7, 5, 7, 5, 7][t], c+`if`(t=6, 1, 0))))
        end:
    a:= n-> b(n, 1, 0):
    seq(a(n), n=0..40);
    # second Maple program:
    a:= proc(n) option remember;
         `if`(n<7, [1, 2, 4, 6, 11, 18, 32][n+1],
         ((n+3)*(307*n^2-2357*n+196)              *a(n-1)
          -(19280-3372*n-5181*n^2+719*n^3)        *a(n-2)
          +(2*(6582+268*n^3-2857*n^2+6959*n))     *a(n-3)
          +(2*(-3307*n^2+1151*n+384*n^3+9052))    *a(n-4)
          -(2*(1016*n^3-12133*n^2+38927*n-28304)) *a(n-5)
          +(4*(27387*n+431*n^3-38420-6108*n^2))   *a(n-6)
          -(4*(n-7))*(67*n-236)*(2*n-11)          *a(n-7)
          )/((2*(n+4))*(24*n^2-148*n-279)))
        end:
    seq(a(n), n=0..40);
  • Mathematica
    b[n_, t_, c_] := b[n, t, c] =
         If[c < 0, 0, If[n == 0, If[c == 0, 1, 0],
         b[n - 1, {2, 4, 6, 4, 6, 4, 6}[[t]], c - If[t == 5, 1, 0]] +
         b[n - 1, {3, 5, 7, 5, 7, 5, 7}[[t]], c + If[t == 6, 1, 0]]]];
    a[n_] := b[n, 1, 0];
    Table[a[n], {n, 0, 40}] (* Jean-François Alcover, Mar 02 2022, after Alois P. Heinz *)

A260505 Number of binary words of length n with exactly one occurrence of subword 010 and exactly two occurrences of subword 101.

Original entry on oeis.org

0, 0, 0, 0, 0, 1, 2, 7, 16, 38, 82, 175, 362, 736, 1468, 2885, 5596, 10736, 20398, 38423, 71818, 133307, 245890, 450970, 822788, 1493992, 2700800, 4862566, 8721608, 15588371, 27770338, 49320863, 87344004, 154263972, 271765362, 477622769, 837519742, 1465470968
Offset: 0

Views

Author

Alois P. Heinz, Nov 11 2015

Keywords

Examples

			a(5) = 1: 10101.
a(6) = 2: 101011, 110101.
a(7) = 7: 0101101, 0110101, 1010110, 1010111, 1011010, 1101011, 1110101.
a(8) = 16: 00101101, 00110101, 01011011, 01011101, 01101011, 01110101, 10101100, 10101110, 10101111, 10110100, 10111010, 11010110, 11010111, 11011010, 11101011, 11110101.
a(9) = 38: 000101101, 000110101, 001011011, ..., 111011010, 111101011, 111110101.
a(10) = 82: 0000101101, 0000110101, 0001011011, ..., 1111011010, 1111101011, 1111110101.
		

Crossrefs

Programs

  • Maple
    gf:= -x^5*(2*x^2-x+1)*(x-1)^3/((x^2-x+1)^2*(x^2+x-1)^4):
    a:= n-> coeff(series(gf,x,n+1),x,n):
    seq(a(n), n=0..40);
  • Mathematica
    LinearRecurrence[{6,-13,10,6,-18,11,6,-10,2,3,-2,-1},{0,0,0,0,0,1,2,7,16,38,82,175},40] (* Harvey P. Dale, Jun 26 2025 *)

Formula

G.f.: -x^5*(2*x^2-x+1)*(x-1)^3/((x^2-x+1)^2*(x^2+x-1)^4).

A303430 Number of binary words of length n with exactly twice as many occurrences of subword 101 as occurrences of subword 010.

Original entry on oeis.org

1, 2, 4, 6, 10, 17, 28, 49, 84, 148, 263, 472, 858, 1568, 2893, 5372, 10034, 18824, 35428, 66898, 126683, 240483, 457334, 870956, 1660850, 3171112, 6061596, 11597587, 22206775, 42551339, 81591256, 156553245, 300565760, 577360360, 1109601934, 2133499936
Offset: 0

Views

Author

Alois P. Heinz, Apr 23 2018

Keywords

Examples

			a(0) = 1: the empty word.
a(1) = 2: 0, 1.
a(2) = 4: 00, 01, 10, 11.
a(3) = 6: 000, 001, 011, 100, 110, 111.
a(4) = 10: 0000, 0001, 0011, 0110, 0111, 1000, 1001, 1100, 1110, 1111.
a(5) = 17: 00000, 00001, 00011, 00110, 00111, 01100, 01110, 01111, 10000, 10001, 10011, 10101, 11000, 11001, 11100, 11110, 11111.
		

Crossrefs

Column k=2 of A303696.

Programs

  • Maple
    b:= proc(n, t, h, c) option remember; `if`(abs(c)>2*n, 0,
         `if`(n=0, 1, b(n-1, [1, 3, 1][t], 2, c-`if`(h=3, 2, 0))
                    + b(n-1, 2, [1, 3, 1][h], c+`if`(t=3, 1, 0))))
        end:
    a:= n-> b(n, 1$2, 0):
    seq(a(n), n=0..50);
Showing 1-4 of 4 results.