A266511 Minimal difference between the smallest and largest of n consecutive large primes that form a symmetric n-tuplet as permitted by divisibility considerations.
0, 2, 12, 8, 36, 16, 60, 26, 84, 34, 132, 46, 168, 56, 180, 74, 240, 82, 252, 94, 324, 106, 372, 118, 420, 134, 432, 142, 492, 146, 540, 158, 600, 166, 648, 178, 660, 194, 720, 202, 780, 214, 816, 226, 840, 254, 912, 262, 1020, 278
Offset: 1
Examples
For n=3, any shortest symmetric n-tuplet has the form (p, p+6, p+12) and thus a(3)=12. From _Jon E. Schoenfield_, Jan 05 2016: (Start) For each n-tuplet (p(1), ..., p(n)) with odd n, let m be its middle prime, i.e., m = p((n+1)/2). Then, since (by symmetry) (p(k) + p(n+1-k))/2 = m for all k = 1..n, we can define the n-tuplet by m and its vector of differences d(j) = m - p(j) for j = 1..(n-1)/2. In other words, given m and d(j) for j = 1..(n-1)/2, the (n-1)/2 primes below m are given by p(j) = m - d(j), and the (n-1)/2 primes above m are given by p(n+1-j) = m + d(j); the difference p(n) - p(1) is thus (m + d(1)) - (m - d(1)) = 2*d(1). For example, one symmetric 7-tuplet of consecutive primes is (12003179, 12003191, 12003197, 12003209, 12003221, 12003227, 12003239), which can be written as (m-30, m-18, m-12, m, m+12, m+18, m+30) where m=12003209; here we have d(1)=30, d(2)=18, d(3)=12. Among all symmetric 7-tuplets of consecutive primes that satisfy divisibility considerations, the minimal value of d(1) is, in fact, 30, so a(7) = 2*30 = 60. For n = 3, 5, ..., 29, the lexicographically first vector (d(1), d(2), ..., d((n-1)/2)) permitted by divisibility considerations is as follows: n| 1 2 3 4 5 6 7 8 9 10 11 12 13 14 --+------------------------------------------------------- 3| 6 5| 18 12 7| 30 18 12 9| 42 30 18 12 11| 66 60 36 24 6 13| 84 66 60 36 24 6 15| 90 84 66 60 36 24 6 17|120 108 90 78 60 48 42 18 19|126 120 114 96 84 54 36 30 6 21|162 150 132 120 108 102 78 48 42 18 23|186 180 150 144 126 96 84 66 60 54 30 25|210 186 180 150 144 126 96 84 66 60 54 30 27|216 210 204 180 126 120 114 96 84 54 36 30 6 29|246 216 210 204 186 174 144 126 90 84 66 60 24 6 (End)
Links
- N. Makarova and C. Rivera, Problem 62. Symmetric k-tuples of consecutive primes.
Extensions
a(1)-a(10) from Natalia Makarova
a(11)-a(14), a(16) from Dmitry Petukhov
a(15) and a(17)-a(18) from Jaroslaw Wroblewski
a(20) from Natalia Makarova and Jaroslaw Wroblewski
a(19), a(21), a(23), a(25), a(27), a(29) from Jon E. Schoenfield, Jan 02 2016, Jan 05 2016
a(22), a(24), a(26), a(28), a(30) from Natalia Makarova, Jul 06 2016
a(31)-a(50) from Vladimir Chirkov, Jul 08 2016
Comments